Provide a link to the catalog admin from the api_admin approval page.

ECOM-4441

openedx/core/djangoapps/api_admin/admin.py

 """Admin views for API managment."""
 from django.contrib import admin
+from django.core.urlresolvers import reverse
+from django.utils.translation import ugettext as _
 
 from config_models.admin import ConfigurationModelAdmin
 from openedx.core.djangoapps.api_admin.models import ApiAccessRequest, ApiAccessConfig
@@ -15,4 +17,21 @@ class ApiAccessRequestAdmin(admin.ModelAdmin):
     readonly_fields = ('user', 'website', 'reason', 'company_name', 'company_address', 'contacted', )
     exclude = ('site',)
 
+    def get_fieldsets(self, request, obj=None):
+        return (
+            (None, {
+                'fields': (
+                    'user', 'website', 'reason', 'company_name', 'company_address',
+                )
+            },),
+            ('Status', {
+                'description': _(
+                    'Once you have approved this request, go to {catalog_admin_url} to set up a catalog for this user.'
+                ).format(
+                    catalog_admin_url='<a href="{0}">{0}</a>'.format(reverse('api_admin:catalog-search'))
+                ),
+                'fields': ('status',),
+            }),
+        )
+
 admin.site.register(ApiAccessConfig, ConfigurationModelAdmin)