Skip to content

E
edx-platform
Commit 9458e539 by Calen Pennington
Options

Adding stripped down 6002x course for testing, along with CMS test for edit pages for same

parent 6bf0e093
Showing with 3516 additions and 1 deletions
cms/djangoapps/contentstore/tests/tests.py
......@@ -205,3 +205,6 @@ class EditTestCase(ContentStoreTestCase):
def test_edit_item_toy(self):
self.check_edit_item('toy')
def test_edit_item_full(self):
self.check_edit_item('full')
common/lib/xmodule/xmodule/vertical_module.py
......@@ -26,7 +26,7 @@ class VerticalModule(XModule):
# TODO: Cache progress or children array?
children = self.get_children()
progresses = [child.get_progress() for child in children]
progress = reduce(Progress.add_counts, progresses)
progress = reduce(Progress.add_counts, progresses, None)
return progress
def get_icon_class(self):
......
common/test/data/full/about/description.html 0 → 100644
6.002x (Circuits and Electronics) is designed to serve as a first course in an undergraduate electrical engineering (EE), or electrical engineering and computer science (EECS) curriculum. At MIT, 6.002 is in the core of department subjects required for all undergraduates in EECS.
The course introduces engineering in the context of the lumped circuit abstraction. Topics covered include: resistive elements and networks; independent and dependent sources; switches and MOS transistors; digital abstraction; amplifiers; energy storage elements; dynamics of first- and second-order networks; design in the time and frequency domains; and analog and digital circuits and applications. Design and lab exercises are also significant components of the course. You should expect to spend approximately 10 hours per week on the course.
\ No newline at end of file
common/test/data/full/about/faq.html 0 → 100644
<ul>
<li>What is the format of the class?
<p>The course will consist of 24 lectures, each lasting 50 minutes. There will be regular assignments consisting of map tests and short essays.</p>
</li>
<li>Are there any prerequisites?
<p>No - anyone and everyone is welcome to take this course.</p>
</li>
<li>What textbook should I buy?
<p>Although the lectures are designed to be self-contained, we recommend (but do not require) that students refer to the book Worlds Together, Worlds Apart: A History of the World: From 1000 CE to the Present (W W Norton, 3rd edition) -- Volume II, which was written specifically for this course.</p>
</li>
<li>Does Harvard award credentials or reports regarding my work in this course?
<p>Princeton does not award credentials or issue reports for student work in this course. However, Coursera could maintain a record of your score on the assessments and, with your permission, verify that score for authorized parties.</p>
</li>
</ul>
common/test/data/full/about/more_info.html 0 → 100644
<section class="who-should-take">
<h3>Who should take this?</h3>
<p>If you're one of the many who have a unquenched interest in the worlds history, you'll love this course.</p>
</section>
<section class="who-shouldnt-take">
<h3>Who shouldn't take this?</h3>
<p>No one. Anyone and everyone is welcome to take this course.</p>
</section>
\ No newline at end of file
common/test/data/full/about/requirements.html 0 → 100644
<p>In order to succeed in this course, you must have taken an AP level physics course in electricity and magnetism. You must know basic calculus and linear algebra and have some background in differential equations. Since more advanced mathematics will not show up until the second half of the course, the first half of the course will include an optional remedial differential equations component for those who need it.</p>
<p>The course web site was developed and tested primarily with Google Chrome. We support current versions of Mozilla Firefox as well. The video player is designed to work with Flash. While we provide a partial non-Flash fallback for the video, as well as partial support for Internet Explorer, other browsers, and tablets, portions of the functionality will be unavailable.</p>
\ No newline at end of file
common/test/data/full/about/syllabus.html 0 → 100644
<ul>
<li><strong>Week 1:</strong> What is World History?</li>
<li><strong>Week 2:</strong> Peoples, Plagues and Plunders</li>
<li><strong>Week 3:</strong> Warfare and Motion</li>
<li><strong>Week 4:</strong> Conquests</li>
<li><strong>Week 5:</strong> The Beginnings of Globalization in the Atlantic Worlds</li>
<li><strong>Week 6:</strong> The Beginnings of Globalization in the Indian Ocean Worlds</li>
<li><strong>Week 7:</strong> The Worlds that Merchants Made</li>
<li><strong>Week 8:</strong> The Seventeenth-Century Crisis</li>
<li><strong>Week 9:</strong> Empire and Enlightenment</li>
<li><strong>Week 10:</strong> The Wealth of Nations</li>
<li><strong>Week 11:</strong> The World in Revolution</li>
<li><strong>Week 12:</strong> States and Nations</li>
<li><strong>Week 13:</strong> Global Frontiers</li>
<li><strong>Week 14:</strong> Empires and Nations</li>
<li><strong>Week 15:</strong> Back to the Future</li>
</ul>
common/test/data/full/about/textbook.html 0 → 100644
<p>The course uses the textbook Foundations of Analog and Digital Electronic Circuits, by Anant Agarwal and Jeffrey H. Lang. Morgan Kaufmann Publishers, Elsevier, July 2005. While recommended, the book is not required: relevant sections will be provided electronically as part of the online course for personal use in connection with this course only. The copyright for the book is owned by Elsevier. The book can be purchased on <a href="http://www.amazon.com/exec/obidos/ASIN/1558607358/ref=nosim/mitopencourse-20">Amazon</a>.</p>
\ No newline at end of file
common/test/data/full/about/video.html 0 → 100644
<iframe width="560" height="315" src="http://www.youtube.com/embed/p2Q6BrNhdh8" frameborder="0" allowfullscreen></iframe>
\ No newline at end of file
common/test/data/full/chapter/Overview.xml 0 → 100644
<sequential>
<video youtube="0.75:izygArpw-Qo,1.0:p2Q6BrNhdh8,1.25:1EeWXzPdhSA,1.50:rABDYkeK0x8" slug="Welcome" format="Video" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never" name="Welcome"/>
<sequential filename="System_Usage_Sequence" slug="System_Usage_Sequence" format="Lecture Sequence" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never" name="System Usage Sequence"/>
<vertical slug="Lab0_Using_the_tools" format="Lab" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never" name="Lab0: Using the tools">
<html slug="html_19" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never"> See the <a href="/section/labintro"> Lab Introduction </a> or <a href="/static/handouts/schematic_tutorial.pdf">Interactive Lab Usage Handout </a> for information on how to do the lab </html>
<problem filename="Lab_0_Using_the_Tools" slug="Lab_0_Using_the_Tools" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="false" name="Lab 0: Using the Tools"/>
</vertical>
<problem filename="Circuit_Sandbox" slug="Circuit_Sandbox" format="Lab" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="false" name="Circuit Sandbox"/>
</sequential>
common/test/data/full/chapter/Week_1.xml 0 → 100644
<sequential>
<sequential filename="Administrivia_and_Circuit_Elements" slug="Administrivia_and_Circuit_Elements" format="Lecture Sequence" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never" name="Administrivia and Circuit Elements"/>
<vertical slug="Basic_Circuit_Analysis" format="Homework" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="closed" rerandomize="per_student" due="March 18" graded="true" name="Basic Circuit Analysis">
<problem filename="H1P1_Energy" slug="H1P1_Energy" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="closed" rerandomize="per_student" due="March 18" graded="true" name="H1P1: Energy"/>
<problem filename="H1P2_Duality" slug="H1P2_Duality" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="closed" rerandomize="per_student" due="March 18" graded="true" name="H1P2: Duality"/>
<problem filename="H1P3_Poor_Workmanship" slug="H1P3_Poor_Workmanship" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="closed" rerandomize="per_student" due="March 18" graded="true" name="H1P3: Poor Workmanship"/>
</vertical>
<problem filename="Resistor_Divider" slug="Resistor_Divider" format="Lab" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never" due="March 18" graded="true" name="Resistor Divider"/>
<html filename="Week_1_Tutorials" slug="Week_1_Tutorials" format="Tutorial Index" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never" name="Week 1 Tutorials"/>
</sequential>
common/test/data/full/course.xml 0 → 100644
<course filename="6.002_Spring_2012" slug="6.002_Spring_2012" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never" name="6.002 Spring 2012"/>
common/test/data/full/course/6.002_Spring_2012.xml 0 → 100644
<sequential>
<chapter filename="Overview" slug="Overview" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never" name="Overview"/>
<chapter filename="Week_1" slug="Week_1" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never" name="Week 1"/>
<chapter slug="Midterm_Exam" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never" name="Midterm Exam">
<sequential slug="Midterm_Exam_1121" format="Midterm" graceperiod="0 day 0 hours 5 minutes 0 seconds" showanswer="attempted" rerandomize="per_student" due="April 30, 12:00" graded="true" name="Midterm Exam">
<vertical slug="vertical_1122" graceperiod="0 day 0 hours 5 minutes 0 seconds" showanswer="attempted" rerandomize="per_student" due="April 30, 12:00" graded="true">
<html filename="Midterm_Exam_1123" slug="Midterm_Exam_1123" graceperiod="0 day 0 hours 5 minutes 0 seconds" rerandomize="per_student" due="April 30, 12:00" graded="true" name="Midterm Exam"/>
</vertical>
<vertical filename="vertical_1124" slug="vertical_1124" graceperiod="0 day 0 hours 5 minutes 0 seconds" showanswer="attempted" rerandomize="per_student" due="April 30, 12:00" graded="true"/>
</sequential>
</chapter>
</sequential>
common/test/data/full/course_settings.json 0 → 100644
{
"GRADER" : [
{
"type" : "Homework",
"min_count" : 12,
"drop_count" : 2,
"short_label" : "HW",
"weight" : 0.15
},
{
"type" : "Lab",
"min_count" : 12,
"drop_count" : 2,
"category" : "Labs",
"weight" : 0.15
},
{
"type" : "Midterm",
"name" : "Midterm Exam",
"short_label" : "Midterm",
"weight" : 0.3
},
{
"type" : "Final",
"name" : "Final Exam",
"short_label" : "Final",
"weight" : 0.4
}
],
"GRADE_CUTOFFS" : {
"A" : 0.87,
"B" : 0.7,
"C" : 0.6
}
}
common/test/data/full/custom_tags/book 0 → 100644
More information given in <a href="/book/${page}">the text</a>.
common/test/data/full/custom_tags/discuss 0 → 100644
<a href='https://6002x.mitx.mit.edu/discussion/questions/scope:all/sort:activity-desc/tags:${tag}/page:1/'> Discussion: ${tag} </a>
\ No newline at end of file
common/test/data/full/custom_tags/image 0 → 100644
<img src="http://pmitros.csail.mit.edu/tutorial/images/${file}" />
common/test/data/full/custom_tags/slides 0 → 100644
Lecture Slides Handout [<a href="/static/handouts/6002-L${lecnum}-oei12-gaps.pdf">Clean </a>][<a href="/static/handouts/6002-L${lecnum}-oei12-gaps-annotated.pdf">Annotated</a>]
\ No newline at end of file
common/test/data/full/custom_tags/videodev 0 → 100644
<video width="560" height="340" controls>
<source src="http://pmitros.csail.mit.edu/tutorial/raw_links/${name}.webm">
</video>
common/test/data/full/html/Final_Exam_2010.html 0 → 100644
<html>
<body>
<center>
Final Exam
</center>
<p>This exam covers weeks 1-13. You may use your calculator, your notes, your book, the internet, or any other auxiliary materials that you think can help you. However, you are not allowed to communicate with any person on any topic associated with this course while you are taking this exam.</p>
<p>
Once you click on the next tab, you will have 24 hours to complete the examination. For each problem you will be allowed exactly three submissions. Your
answers to that problem will be checked after each submission, so you
can fix mistakes you may have made, within the three-submission limit.
Your most recently checked answer is the answer that will contribute to your grade on the exam.
</p>
<p>
Each answer box on the exam contributes equally to your grade on the exam, regardless of how they are grouped as problems.
</p>
</body>
</html>
common/test/data/full/html/FirstOrderSystemHint.xml 0 → 100644
Hint
<br/><br/>
Remember that the time evolution of any variable \(x(t)\) governed by
a first-order system with a time-constant \(\tau\) for a time \(t) between an initial
value \(x(t_0)\) and a final value \(x(\infty)\) is the following:
<br/><br/>
\(x(t) = x(\infty) + (x(t_0) - x(\infty)) e^(-(t-t_0)/\tau)\)
<br/><br/>
common/test/data/full/html/Lab2A.html 0 → 100644
<script type="text/javascript">
$(document).ready(function() {
$("#r1_slider").slider({
value: 1, min: 1, max: 10, step: 1, slide: schematic.component_slider,
schematic: "ctrls", component: "R1", property: "r", analysis: "dc",
})
$("#r2_slider").slider({
value: 1, min: 1, max: 10, step: 1, slide: schematic.component_slider,
schematic: "ctrls", component: "R2", property: "r", analysis: "dc",
})
$("#r3_slider").slider({
value: 1, min: 1, max: 10, step: 1, slide: schematic.component_slider,
schematic: "ctrls", component: "R3", property: "r", analysis: "dc",
})
$("#r4_slider").slider({
value: 1, min: 1, max: 10, step: 1, slide: schematic.component_slider,
schematic: "ctrls", component: "R4", property: "r", analysis: "dc",
})
$("#slider").slider(); });
</script>
<b>Lab 2A: Superposition Experiment</b>
<br><br><i>Note: This part of the lab is just to develop your intuition about
superposition. There are no responses that need to be checked.</i>
<br/><br/>Circuits with multiple sources can be hard to analyze as-is. For example, what is the voltage
between the two terminals on the right of Figure 1?
<center>
<input width="425" type="hidden" height="150" id="schematic1" parts="" analyses="" class="schematic ctrls" name="test2" value="[[&quot;w&quot;,[160,64,184,64]],[&quot;w&quot;,[160,16,184,16]],[&quot;w&quot;,[64,16,112,16]],[&quot;w&quot;,[112,64,88,64]],[&quot;w&quot;,[64,64,88,64]],[&quot;g&quot;,[88,64,0],{},[&quot;0&quot;]],[&quot;w&quot;,[112,64,160,64]],[&quot;w&quot;,[16,64,64,64]],[&quot;r&quot;,[160,16,0],{&quot;name&quot;:&quot;R4&quot;,&quot;r&quot;:&quot;1&quot;},[&quot;1&quot;,&quot;0&quot;]],[&quot;r&quot;,[160,16,1],{&quot;name&quot;:&quot;R3&quot;,&quot;r&quot;:&quot;1&quot;},[&quot;1&quot;,&quot;2&quot;]],[&quot;i&quot;,[112,64,6],{&quot;name&quot;:&quot;&quot;,&quot;value&quot;:&quot;6A&quot;},[&quot;0&quot;,&quot;2&quot;]],[&quot;r&quot;,[64,16,0],{&quot;name&quot;:&quot;R2&quot;,&quot;r&quot;:&quot;1&quot;},[&quot;2&quot;,&quot;0&quot;]],[&quot;r&quot;,[64,16,1],{&quot;name&quot;:&quot;R1&quot;,&quot;r&quot;:&quot;1&quot;},[&quot;2&quot;,&quot;3&quot;]],[&quot;v&quot;,[16,16,0],{&quot;name&quot;:&quot;&quot;,&quot;value&quot;:&quot;8V&quot;},[&quot;3&quot;,&quot;0&quot;]],[&quot;view&quot;,-24,0,2]]"/>
Figure 1. Example multi-source circuit
</center>
<br/><br/>We can use superposition to make the analysis much easier.
The circuit in Figure 1 can be decomposed into two separate
subcircuits: one involving only the voltage source and one involving only the
current source. We'll analyze each circuit separately and combine the
results using superposition. Recall that to decompose a circuit for
analysis, we'll pick each source in turn and set all the other sources
to zero (i.e., voltage sources become short circuits and current
sources become open circuits). The circuit above has two sources, so
the decomposition produces two subcircuits, as shown in Figure 2.
<center>
<table><tr><td>
<input style="display:inline;" width="425" type="hidden" height="150" id="schematic2" parts="" analyses="" class="schematic ctrls" name="test2" value="[[&quot;w&quot;,[160,64,184,64]],[&quot;w&quot;,[160,16,184,16]],[&quot;w&quot;,[64,16,112,16]],[&quot;w&quot;,[112,64,88,64]],[&quot;w&quot;,[64,64,88,64]],[&quot;g&quot;,[88,64,0],{},[&quot;0&quot;]],[&quot;w&quot;,[112,64,160,64]],[&quot;w&quot;,[16,64,64,64]],[&quot;r&quot;,[160,16,0],{&quot;name&quot;:&quot;R4&quot;,&quot;r&quot;:&quot;1&quot;},[&quot;1&quot;,&quot;0&quot;]],[&quot;r&quot;,[160,16,1],{&quot;name&quot;:&quot;R3&quot;,&quot;r&quot;:&quot;1&quot;},[&quot;1&quot;,&quot;2&quot;]],[&quot;r&quot;,[64,16,0],{&quot;name&quot;:&quot;R2&quot;,&quot;r&quot;:&quot;1&quot;},[&quot;2&quot;,&quot;0&quot;]],[&quot;r&quot;,[64,16,1],{&quot;name&quot;:&quot;R1&quot;,&quot;r&quot;:&quot;1&quot;},[&quot;2&quot;,&quot;3&quot;]],[&quot;v&quot;,[16,16,0],{&quot;name&quot;:&quot;&quot;,&quot;value&quot;:&quot;8V&quot;},[&quot;3&quot;,&quot;0&quot;]],[&quot;view&quot;,-24,0,2]]"/>
(a) Subcircuit for analyzing contribution of voltage source
</td><td>
<input width="425" type="hidden" height="150" id="schematic3" parts="" analyses="" class="schematic ctrls" name="test2" value="[[&quot;w&quot;,[16,16,16,64]],[&quot;w&quot;,[160,64,184,64]],[&quot;w&quot;,[160,16,184,16]],[&quot;w&quot;,[64,16,112,16]],[&quot;w&quot;,[112,64,88,64]],[&quot;w&quot;,[64,64,88,64]],[&quot;g&quot;,[88,64,0],{},[&quot;0&quot;]],[&quot;w&quot;,[112,64,160,64]],[&quot;w&quot;,[16,64,64,64]],[&quot;r&quot;,[160,16,0],{&quot;name&quot;:&quot;R4&quot;,&quot;r&quot;:&quot;1&quot;},[&quot;1&quot;,&quot;0&quot;]],[&quot;r&quot;,[160,16,1],{&quot;name&quot;:&quot;R3&quot;,&quot;r&quot;:&quot;1&quot;},[&quot;1&quot;,&quot;2&quot;]],[&quot;i&quot;,[112,64,6],{&quot;name&quot;:&quot;&quot;,&quot;value&quot;:&quot;6A&quot;},[&quot;0&quot;,&quot;2&quot;]],[&quot;r&quot;,[64,16,0],{&quot;name&quot;:&quot;R2&quot;,&quot;r&quot;:&quot;1&quot;},[&quot;2&quot;,&quot;0&quot;]],[&quot;r&quot;,[64,16,1],{&quot;name&quot;:&quot;R1&quot;,&quot;r&quot;:&quot;1&quot;},[&quot;2&quot;,&quot;3&quot;]],[&quot;view&quot;,-24,0,2]]"/>
(b) Subcircuit for analyzing contribution of current source
</td></tr></table>
<br>Figure 2. Decomposition of Figure 1 into subcircuits
</center>
<br/>Let's use the DC analysis capability of the schematic tool to see superposition
in action. The sliders below control the resistances of R1, R2, R3 and R4 in all
the diagrams. As you move the sliders, the schematic tool will adjust the appropriate
resistance, perform a DC analysis and display the node voltages on the diagrams. Here's
what you want to observe as you play with the sliders:
<ul style="margin-left:2em;margin-top:1em;margin-right:2em;margin-bottom:1em;">
<i>The voltage for a node in Figure 1 is the sum of the voltages for
that node in Figures 2(a) and 2(b), just as predicted by
superposition. (Note that due to round-off in the display of the
voltages, the sum of the displayed voltages in Figure 2 may only be within
.01 of the voltages displayed in Figure 1.)</i>
</ul>
<br>
<center>
<table><tr valign="top">
<td>
<table>
<tr valign="top">
<td>R1</td>
<td>
<div id="r1_slider" style="width:200px; height:10px; margin-left:15px"></div>
</td>
</tr>
<tr valign="top">
<td>R2</td>
<td>
<div id="r2_slider" style="width:200px; height:10px; margin-left:15px; margin-top:10px;"></div>
</td>
</tr>
<tr valign="top">
<td>R3</td>
<td>
<div id="r3_slider" style="width:200px; height:10px; margin-left:15px; margin-top:10px;"></div>
</td>
</tr>
<tr valign="top">
<td>R4</td>
<td>
<div id="r4_slider" style="width:200px; height:10px; margin-left:15px; margin-top:10px;"></div>
</td>
</tr>
</table>
</td></tr></table>
</center>
common/test/data/full/html/Midterm.html 0 → 100644
<center>
Midterm Exam
</center>
<p>
This is a twenty four hour examination. You can start the exam when it is
convenient for you, but you must complete this examination by 12:00pm (noon)
GMT on April 30th. Please look up what time this is in your local time zone.
</p>
<p>
When you open the next page, you will have started the examination.
You do not need to start now: you will not be timed until you open the
next page. Once you have opened the next page page you must complete
the exam and make your final submission within twenty four hours of starting
the exam.
</p>
<p>
You may use any notes, computational, or auxiliary materials that you
think can help you. However, you may not communicate with any person
about this examination while working on it. Furthermore, you may not
communicate about the exam until the exam has been closed for everyone.
</p>
<p>
For each problem you will be allowed exactly three submissions. Your
answers to that problem will be checked after each submission, so you
can fix mistakes you may have made, within the three-submission limit.
</p>
<p>
If you want to go back and study some more before starting this
exam you can do so. Good Luck!
</p>
common/test/data/full/html/Midterm_Exam_1080.html 0 → 100644
<html>
<body>
<center>
Midterm Exam
</center>
<p>
This is a twenty four hour examination. You can start the exam when it is
convenient for you, but you must complete this examination by 12:00pm (noon)
GMT on April 30th. Please look up what time this is in your local time zone.
</p>
<p>
When you open the next page, you will have started the examination.
You do not need to start now: you will not be timed until you open the
next page. Once you have opened the next page page you must complete
the exam and make your final submission within twenty four hours of starting
the exam.
</p>
<p>
You may use any notes, computational, or auxiliary materials that you
think can help you. However, you may not communicate with any person
about this examination while working on it. Furthermore, you may not
communicate about the exam until the exam has been closed for everyone.
</p>
<p>
For each problem you will be allowed exactly three submissions. Your
answers to that problem will be checked after each submission, so you
can fix mistakes you may have made, within the three-submission limit.
</p>
<p>
If you want to go back and study some more before starting this
exam you can do so. Good Luck!
</p>
</body>
</html>
common/test/data/full/html/Midterm_Exam_1123.html 0 → 100644
<html>
<body>
<center>
Midterm Exam
</center>
<p>
This is a twenty four hour examination. You can start the exam when it is
convenient for you, but you must complete this examination by 12:00pm (noon)
GMT on April 30th. Please look up what time this is in your local time zone.
</p>
<p>
When you open the next page, you will have started the examination.
You do not need to start now: you will not be timed until you open the
next page. Once you have opened the next page page you must complete
the exam and make your final submission within twenty four hours of starting
the exam.
</p>
<p>
You may use any notes, computational, or auxiliary materials that you
think can help you. However, you may not communicate with any person
about this examination while working on it. Furthermore, you may not
communicate about the exam until the exam has been closed for everyone.
</p>
<p>
For each problem you will be allowed exactly three submissions. Your
answers to that problem will be checked after each submission, so you
can fix mistakes you may have made, within the three-submission limit.
</p>
<p>
If you want to go back and study some more before starting this
exam you can do so. Good Luck!
</p>
</body>
</html>
common/test/data/full/html/Week_13_Tutorials.html 0 → 100644
<html>
<body>
<h1>Week 13 Tutorials</h1>
<section class="tutorials">
<h2> Basic Tutorials </h2>
<ul>
<li><a href="/section/wk13_solder">Soldering</a> -- Steve
Finberg, one of the pioneers in from Draper Lab, talks about
soldering. </li>
</ul>
<h2> Bonus Tutorials </h2>
<ul>
<li><a href="/section/wk13_FreqResp">Frequency Response
Curves</a> -- We explain several techniques for understanding
and approximating Bode plots. </li>
</ul>
</section>
</body>
</html>
common/test/data/full/html/Week_1_Tutorials.html 0 → 100644
<html>
<body>
<h1>Week 1 Tutorials</h1>
<section class="tutorials">
<h2> Introduction </h2>
<ul>
<li><a href="/section/intro"> Welcome! </a> - We introduce
ourselves and explain the tutorial format. </li>
</ul>
<h2>Basic Tutorials </h2>
<ul>
<li><a href="/section/circuit_abstraction">The Circuit
Abstraction</a> - We look at a lightbulb, and see that abstracting
away the circuit from the geometry of the wiring has no visible
effect. </li>
<li><a href="/section/a_real_circuit/">Lightbulb Circuit</a> - We
look at the voltage across a lightbulb with a multimeter, and
confirm the device is symmetric. In the process, we see reference
directions for currents, voltages, and polarity for powers. </li>
<li><a href="/section/parallel_resistors">Parallel Resistors</a> -
An explanation of equivalent circuits in the context of parallel
resistors.</li>
<li><a href="/section/series_and_parallel">Combination of Series
and Parallel</a> - Slightly more complex networks of resistors
simplified with equivalent networks.</li>
<li><a href="/section/3r_nodal">Nodal Analysis</a> - A simple
example of nodal analysis.</li>
<li><a href="/section/floating_voltage_3r">Floating Voltage</a> -
Nodal analysis with a floating source.</li>
<li><a href="/section/combination_rules">Combination Rules</a> -
We show how to apply combination rules to solving simple
circuits.</li>
</ul>
<h2>Worked Problems </h2>
<p> For the first week, we work through <a href="http://ocw.mit.edu/courses/electrical-engineering-and-computer-science/6-002-circuits-and-electronics-spring-2007/assignments/hw1.pdf"> the first problem set from 2007</a></p>
<ul>
<li><a href="/section/exercise_1_1">OCW Exercise 1-1</a>: Find voltages in a simple series and parallel circuit, and show power is conserved</li>
<li><a href="/section/ex_1_2">OCW Exercise 1-2</a> - Synthesize a network of 3/5k and 5/3k from at most four 1k resistors</li>
<li><a href="/section/problem_1-1">OCW Problem 1-1/Textbook 2.7</a> - Find the current through a resistor in a network of resistors</li>
<li><a href="/section/problem_1-2_part1">OCW Problem 1-2</a> - Analyze long chains of resistors (similar to transmission lines or R1R2 ladders) </li>
<li><a href="/section/problem_1_3">OCW Problem 1-3 </a> - Reverse engineer a black-box resistor network</li>
</ul>
<hr/>
<p> Since the course has students from a diverse set of backgrounds, the first week's tutorials includes several extra segments, worked out with greater detail, to help bring everyone up to speed. </p>
</section>
</body>
</html>
common/test/data/full/html/linearity_clarify.html 0 → 100644
Clarification of the term "Linear"
<p>
The term "linear" is very clear when applied to a
mathematical function. A function F is linear if and only
if it obeys homogeneity and superposition:
</p><p>
Homogeneity: F(cx) = cF(x)
<br/>
Superposition: F(x+y) = F(x) + F(y)
</p><p>
In the context of what we have seen so far, the only
elements that are linear as mathematical functions are
resistors. An independent voltage source or an independent
current source is not a linear element. (There are also
linear dependent sources, linear capacitors and linear
inductors, but we have not yet introduced them in our class.
You will see them later.)
</p><p>
Formally, a circuit composed of only linear elements is a
linear circuit. When we add independent sources to a linear
circuit as inputs, we get a circuit that is not linear
because it has an offset: its v-i characteristic at a pair
of exposed terminals may not pass through the origin.
However, we can make a Thevenin or Norton equivalent model
of such a circuit: the Thevenin resistance summarizes the
effect of the linear elements and the Thevenin voltage
summarizes the effect of the independent sources.
</p><p>
However the term "linear," when applied to an electrical
circuit often takes on an informal meaning. We often say
that a circuit containing only linear elements and
independent sources is a "linear circuit." So, in the
informal sense, a linear circuit is one where we can apply
the Thevenin or Norton theorems to summarize the behavior at
a pair of exposed terminals.
</p><p>
Sorry for the confusion of words -- natural language is like
that!
</p>
common/test/data/full/html/linearity_clarify.xml 0 → 100644
Clarification of the term "Linear"
<p>
The term "linear" is very clear when applied to a
mathematical function. A function F is linear if and only
if it obeys homogeneity and superposition:
</p><p>
Homogeneity: F(cx) = cF(x)
<br/>
Superposition: F(x+y) = F(x) + F(y)
</p><p>
In the context of what we have seen so far, the only
elements that are linear as mathematical functions are
resistors. An independent voltage source or an independent
current source is not a linear element. (There are also
linear dependent sources, linear
inductors, and other linear elements, but we have not yet introduced them in our class.
You will see them later.)
</p><p>
Formally, a circuit composed of only linear elements is a
linear circuit. When we add independent sources to a linear
circuit as inputs, we get a circuit that is not linear
because it has an offset: its v-i characteristic at a pair
of exposed terminals may not pass through the origin.
However, we can make a Thevenin or Norton equivalent model
of such a circuit: the Thevenin resistance summarizes the
effect of the linear elements and the Thevenin voltage
summarizes the effect of the independent sources.
</p><p>
However the term "linear," when applied to an electrical
circuit often takes on an informal meaning. We often say
that a circuit containing only linear elements and
independent sources is a "linear circuit." So, in the
informal sense, a linear circuit is one where we can apply
the Thevenin or Norton theorems to summarize the behavior at
a pair of exposed terminals.
</p><p>
Sorry for the confusion of words -- natural language is like
that!
</p>
common/test/data/full/html/schematic_tutorial.html 0 → 100644
<p/><b>Usage Summary:</b>
<table style="border-spacing:2em; border-collapse: separate;">
<tr>
<td style="width:10em;">Add a component</td>
<td>Click on the component in the parts bin (the columns of part icons to
the right of the diagram area) and drag it onto the diagram. Release
the mouse when the component is in the correct position.
</td>
</tr>
<tr>
<td>Move a component</td>
<td>Click to select a component in the diagram (it will turn green)
and then drag it to its new location. You can use shift-click to add
a component to the current selection. Or you can click somewhere in
the diagram that is not on top of a component and drag out a selection
rectangle -- components intersecting the rectangle will be added to
the current selection.
</td>
</tr>
<tr>
<td>Rotate a component</td>
<td>Click to select a component in the diagram (it will turn green)
and then type the letter "r" on the keyboard. The component will
be rotated 90 degrees. Additional rotations will move the component
through its eight possible orientations (4 compass points and their
reflections).
</td>
</tr>
<tr>
<td>Delete a component</td>
<td>Click to select the component in the diagram (shift-click to
select multiple components) then type DEL or BACKSPACE on your
keyboard.
</td>
</tr>
<tr>
<td>Change a component's properties</td>
<td>Double click on the component. This will bring up an Edit Properties
window that has input fields for each of the component's properties.
Click OK to change the values. Click CANCEL or the window's close
button to abort the changes. Numeric values can be entered using
engineeering notation:
<center><table style="border-collapse:separate; border-spacing:1em;">
<tr><th>suffix</th><th>multiplier</th> <th style="width:3em"></th> <th>suffix</th><th>multiplier</th></tr>
<tr><td>T</td><td>\(10^{12}\)</td> <td></td> <td>u</td><td>\(10^{-6}\)</td></tr>
<tr><td>G</td><td>\(10^{9}\)</td> <td></td> <td>n</td><td>\(10^{-9}\)</td></tr>
<tr><td>M</td><td>\(10^{6}\)</td> <td></td> <td>p</td><td>\(10^{-12}\)</td></tr>
<tr><td>k</td><td>\(10^{3}\)</td> <td></td> <td>f</td><td>\(10^{-15}\)</td></tr>
<tr><td>m</td><td>\(10^{-3}\)</td></tr>
</table></center>
</td>
</tr>
<tr>
<td>Add a wire</td>
<td>Wires start at connection points, the open circles that
appear at the terminals of components or the ends of wires.
Click on a connection point to start a wire -- a green wire
will appear with one end anchored at the starting point.
Drag the mouse and release the mouse button when the other
end of the wire is positioned as you wish. Once a wire has
been added to the diagram it can be manipulated like any other
component.
</td>
</tr>
</table>
common/test/data/full/html/sound_labs/mosfet_amplifier.html 0 → 100644
<script type="text/javascript" src="/static/courses/6002/js/sound_labs/sound.js"></script>
<script type="text/javascript" src="/static/courses/6002/js/sound_labs/plotter.js"></script>
<script type="text/javascript" src="/static/courses/6002/js/sound_labs/circuit.js"></script>
<script type="text/javascript" src="/static/courses/6002/js/sound_labs/mosfet_amplifier.js"></script>
<h2>LAB 5B: MOSFET AMPLIFIER EXPERIMENT</h2>
<section class="problem">
<startouttext />
<p>Note: This part of the lab is just to develop your intuition about
amplifiers and biasing, and to have fun with music! There are no responses
that need to be checked.</p>
<p>The graph plots the selected voltages from the amplifier circuit below. You
can also listen to various signals by selecting from the radio buttons to
the right of the graph. This way you can both see and hear various signals.
You can use the sliders to the right of the amplifier circuit to control
various parameters of the MOSFET and the amplifier. The parameter \(V_{MAX}\)
sets the maximum range on the plots. You can also select an input voltage
type (e.g., sine wave, square wave, various types of music) using the drop
down menu to the right of the graph. When describing AC signals, the
voltages on the sliders refer to peak-to-peak values.</p>
<p>1. To begin your first experiment, go ahead and use the pull down menu to
select a sine wave input. Then, adjust the sliders to an approximate
baseline setting shown below.</p>
<p>Baseline setting of sliders:
<br />
\(V_{S}=1.6V\), \(v_{IN}=3V\), \(Frequency=1000Hz\), \(V_{BIAS}=2.5V\), \(R=10K\Omega\), \(k=1mA/V^{2}\), \(V_{T}=1V\), \(V_{MAX}=2V\).</p>
<p>You will observe in the plot that the baseline setting of the sliders for
the various amplifiers parameters produces a distorted sine wave signal for
\(v_{OUT}\). Next, go ahead and select one of the music signals as the input and
listen to each of \(v_{IN}\) and \(v_{OUT}\), and confirm for yourself that the
output sounds distorted for the chosen slider settings. You will notice
that the graph now plots the music signal waveforms. Think about all the
reasons why the amplifier is producing a distorted output.</p>
<p>2. For the second experiment, we will study the amplifier's small signal
behavior. Select a sine wave as the input signal. To study the small
signal behavior, reduce the value of \(v_{IN}\) to 0.1V (peak-to-peak) by
using the \(v_{IN}\) slider. Keeping the rest of the parameters at their
baseline settings, derive an appropriate value of \(V_{BIAS}\) that will ensure
saturation region operation for the MOSFET for the 0.1V peak-to-peak swing
for \(v_{IN}\). Make sure to think about both positive and negative excursions
of the signals.</p>
</p>Next, use the \(V_{BIAS}\) slider to choose your computed value for \(V_{BIAS}\) and
see if the observed plot of \(v_{OUT}\) is more or less distortion free. If
your calculation was right, then the output will indeed be distortion free.</p>
<p>Next, select one of the music signals as the input and listen to each of
\(v_{IN}\) and \(v_{OUT}\), and confirm for yourself that the output sounds much
better than in Step 1. Also, based on sound volume, confirm that \(v_{OUT}\) is
an amplified version of \(v_{IN}\).</p>
<p>3. Now go ahead and experiment with various other settings while listening
to the music signal at \(v_{OUT}\). Observe the plots and listen to \(v_{OUT}\) as
you change, for example, the bias voltage \(V_{BIAS}\). You will notice that
the amplifier distorts the input signal when \(V_{BIAS}\) becomes too small, or
when it becomes too large. You can also experiment with various values of
\(v_{IN}\), \(R_{L}\), etc., and see how they affect the amplification and distortion.</p>
<endouttext />
</section>
<section class="tool-wrapper">
<div id="controlls-container">
<div class="graph-controls">
<div class="music-wrapper">
<select id="musicTypeSelect" size="1">
<option value = "0">Zero Input</option>
<option value = "1">Unit Impulse</option>
<option value = "2">Unit Step</option>
<option selected="selected" value = "3">Sine Wave</option>
<option value = "4">Square Wave</option>
<option value = "5">Classical Music</option>
<option value = "6">Folk Music</option>
<option value = "7">Jazz Music</option>
<option value = "8">Reggae Music</option>
</select>
<input id="playButton" type="button" value="Play" />
</div>
<div class="inputs-wrapper">
<div id="graph-output">
<p>Graph:</p>
<ul>
<li><label for="vinCheckbox"><input id="vinCheckbox" type="checkbox" checked="yes"/>v<sub>IN</sub></label></li>
<li><label for="voutCheckbox"><input id="voutCheckbox" type="checkbox" checked="yes"/>v<sub>OUT</sub></label> </li>
<li><label for="vrCheckbox"><input id="vrCheckbox" type="checkbox"/>v<sub>R</sub></label></li>
</ul>
</div>
<div id="graph-listen">
<p>Listen to:</p>
<ul>
<li><label for="vinRadioButton"><input id="vinRadioButton" type="radio" checked="yes" name="listenToWhat"/>v<sub>IN</sub></label></li>
<li><label for="voutRadioButton"><input id="voutRadioButton" type="radio" name="listenToWhat"/>v<sub>OUT</sub></label></li>
<li><label for="vrRadioButton"><input id="vrRadioButton" type="radio" name="listenToWhat"/>v<sub>R</sub></label></li>
</ul>
</div>
</div>
</div>
<div class="schematic-sliders">
<div class="slider-label" id="vs"></div>
<div class="slider" id="vsSlider"></div>
<div class="slider-label" id="vin"></div>
<div class="slider" id="vinSlider"></div>
<div class="slider-label" id="freq"></div>
<div class="slider" id="freqSlider"></div>
<div class="slider-label" id="vbias"></div>
<div class="slider" id="vbiasSlider"></div>
<div class="slider-label" id="r"></div>
<div class="slider" id="rSlider"></div>
<div class="slider-label" id="k"></div>
<div class="slider" id="kSlider"></div>
<div class="slider-label" id="vt"></div>
<div class="slider" id="vtSlider"></div>
<div class="slider-label" id="vmax"></div>
<div class="slider" id="vmaxSlider"></div>
</div>
</div>
<div id="graph-container">
<canvas id="graph" width="500" height="500">Your browser must support the Canvas element and have JavaScript enabled to view this tool.</canvas>
<canvas id="diag1" width="500" height="500">Your browser must support the Canvas element and have JavaScript enabled to view this tool.</canvas>
</div>
</section>
common/test/data/full/html/sound_labs/rc_filters.html 0 → 100644
<script type="text/javascript" src="/static/courses/6002/js/sound_labs/sound.js"></script>
<script type="text/javascript" src="/static/courses/6002/js/sound_labs/plotter.js"></script>
<script type="text/javascript" src="/static/courses/6002/js/sound_labs/circuit.js"></script>
<script type="text/javascript" src="/static/courses/6002/js/sound_labs/rc_filters.js"></script>
<h2>LAB 10B: RC FILTERS WITH FREQUENCY RESPONSE EXPERIMENT</h2>
<section class="problem">
<startouttext />
<p>Note: Use this part of the lab to build your intuition about filters and frequency response, and to have fun with music! There are no responses that need to be checked.</p>
<p>Recall from the audio lab in Week 5 that the graph plots the selected voltages from the circuit shown below. This week the circuit is an RC filter. You can also listen to various signals by selecting from the radio buttons to the right of the graph. This way you can both see and hear various signals. You can use the sliders to the right of the circuit to control various circuit and input signal parameters. (Note that you can get finer control of some of the slider values by clicking on the slider and using the arrow keys). Recall that the parameter \(V_{MAX}\) sets the maximum range on the graph. You can also select an input voltage type (e.g., sine wave, square wave, various types of music) using the drop down menu to the right of the graph. When describing AC signals, the voltages on the sliders refer to peak-to-peak values.</p>
<p>1. To begin your first experiment, use the pull down menu to select a sine wave input. Then, adjust the sliders to these approximate baseline settings:
<br />
\(v_{IN} = 3V\), \(Frequency = 1000 Hz\), \(V_{BIAS} = 0V\), \(R = 1K\Omega\), \(v_C(0) = 0V\), \(C = 110nF\), \(V_{MAX} = 2V\).
<br />
Observe the waveforms for \(v_{IN}\) and \(v_C\) in the graph. You can also listen to \(v_{IN}\) and \(v_C\). You will observe that the amplitude of \(v_C\) is slightly smaller than the amplitude of \(v_{IN}\).
<br />
Compute the break frequency of the filter circuit for the given circuit parameters. (Note that the break frequency is also called the cutoff frequency or the corner frequency).
<br />
Change the frequency of the sinusoid so that it is approximately 3 times the break frequency.
<br />
Observe the waveforms for \(v_{IN}\) and \(v_C\) in the graph. Also listen to \(v_{IN}\) and \(v_C\). Think about why the sinusoid at \(v_C\) is significantly more attenuated than the original 1KHz sinusoid.
<br />
Keeping the input signal unchanged, observe the waveforms for \(v_{IN}\) and \(v_R\) in the graph. Also listen to \(v_{IN}\) and \(v_R\). Think about why the sinusoid at \(v_R\) is significantly louder than the sinusoid at \(v_C\).</p>
<p>2. Next, use the pull down menu to select a music signal of your choice. Adjust the sliders to the approximate baseline settings:
<br />
\(v_{IN} = 3V\), \(V_{BIAS} = 0V\), \(R = 1K\Omega\), \(v_C(0) = 0V\), \(C = 110nF\), \(V_{MAX} = 2V\).
<br />
Listen to the signals at \(v_{IN}\) and \(v_C\). Notice any difference between the signals?
<br />
Next, increase the capacitance value and observe the difference in the sound of \(v_{IN}\) and \(v_C\) as the capacitance increases. You should notice that the higher frequency components of \(v_C\) are attenuated as the capacitance is increased.
Convince yourself that when the signal is taken at \(v_C\), the circuit behaves like a low-pass filter.</p>
<p>3. Re-adjust the sliders to the approximate baseline settings:
<br />
\(v_{IN} = 3V\), \(V_{BIAS} = 0V\), \(R = 1K\Omega\), \(v_C(0) = 0V\), \(C = 110nF\), \(V_{MAX} = 2V\).
<br />
Try to create a high-pass filter from the same circuit by taking the signal output across a different element and possibly changing some of the element values.
</p>
<endouttext />
</section>
<section class="tool-wrapper">
<div id="controlls-container">
<div class="graph-controls">
<div class="music-wrapper">
<select id="musicTypeSelect" size="1">
<option value = "0">Zero Input</option>
<option value = "1">Unit Impulse</option>
<option value = "2">Unit Step</option>
<option selected="selected" value = "3">Sine Wave</option>
<option value = "4">Square Wave</option>
<option value = "5">Classical Music</option>
<option value = "6">Folk Music</option>
<option value = "7">Jazz Music</option>
<option value = "8">Reggae Music</option>
</select>
<input id="playButton" type="button" value="Play" />
</div>
<div class="inputs-wrapper">
<div id="graph-output">
<p>Graph:</p>
<ul>
<li><label for="vinCheckbox"><input id="vinCheckbox" type="checkbox" checked="yes"/>v<sub>IN</sub></label></li>
<li><label for="vcCheckbox"><input id="vcCheckbox" type="checkbox" checked="yes"/>v<sub>C</sub></label> </li>
<li><label for="vrCheckbox"><input id="vrCheckbox" type="checkbox"/>v<sub>R</sub></label></li>
</ul>
</div>
<div id="graph-listen">
<p>Listen to:</p>
<ul>
<li><label for="vinRadioButton"><input id="vinRadioButton" type="radio" checked="yes" name="listenToWhat"/>v<sub>IN</sub></label></li>
<li><label for="vcRadioButton"><input id="vcRadioButton" type="radio" name="listenToWhat"/>v<sub>C</sub></label></li>
<li><label for="vrRadioButton"><input id="vrRadioButton" type="radio" name="listenToWhat"/>v<sub>R</sub></label></li>
</ul>
</div>
</div>
</div>
<div class="schematic-sliders">
<div class="slider-label" id="fc">f<sub>C</sub> = </div>
<div class="slider-label" id="vin"></div>
<div class="slider" id="vinSlider"></div>
<div class="slider-label" id="freq"></div>
<div class="slider" id="freqSlider"></div>
<div class="slider-label" id="vbias"></div>
<div class="slider" id="vbiasSlider"></div>
<div class="slider-label" id="r"></div>
<div class="slider" id="rSlider"></div>
<div class="slider-label" id="vc0"></div>
<div class="slider" id="vc0Slider"></div>
<div class="slider-label" id="c"></div>
<div class="slider" id="cSlider"></div>
<div class="slider-label" id="vmax"></div>
<div class="slider" id="vmaxSlider"></div>
</div>
</div>
<div id="graph-container">
<div id="graphTabs">
<ul>
<li><a href="#time">Time</a></li>
<li><a href="#magnitude">Magnitude</a></li>
<li><a href="#phase">Phase</a></li>
</ul>
<canvas id="time" width="500" height="500">Your browser must support the Canvas element and have JavaScript enabled to view this tool.</canvas>
<canvas id="magnitude" width="500" height="500">Your browser must support the Canvas element and have JavaScript enabled to view this tool.</canvas>
<canvas id="phase" width="500" height="500">Your browser must support the Canvas element and have JavaScript enabled to view this tool.</canvas>
</div>
<canvas id="diag2" width="500" height="500">Your browser must support the Canvas element and have JavaScript enabled to view this tool.</canvas>
</div>
</section>
common/test/data/full/html/sound_labs/series_rlc.html 0 → 100644
<script type="text/javascript" src="/static/courses/6002/js/sound_labs/sound.js"></script>
<script type="text/javascript" src="/static/courses/6002/js/sound_labs/plotter.js"></script>
<script type="text/javascript" src="/static/courses/6002/js/sound_labs/circuit.js"></script>
<script type="text/javascript" src="/static/courses/6002/js/sound_labs/series_rlc.js"></script>
<h2>SERIES RLC CIRCUIT WITH FREQUENCY RESPONSE EXPERIMENT</h2>
<section class="problem">
<startouttext />
<p>\(I(s) = \frac{1}{R + Ls + 1/Cs}V_{in}(s) = \frac{s/L}{s^2 + sR/L + 1/LC}V_{in}(s)\)</p>
<p>\(I(s) = \frac{s/L}{s^2 + 2\alpha s + \omega_0^2}V_{in}(s)\)</p>
<p>\(\omega_0 = \frac{1}{\sqrt{LC}} , \alpha = \frac{R}{2L}\)</p>
<p>Band-Pass Filter:</p>
<p>\(V_r(s) = RI(s) = \frac{sR/L}{s^2 + 2\alpha s + \omega_0^2}V_{in}(s) = \frac{2\alpha s}{s^2 + 2\alpha s + \omega_0^2}V_{in}(s) = \frac{2\alpha s}{(s-s_1)(s-s_2)}V_{in}(s)\)</p>
<p>Gain magnitude: \(G_R = \frac{2\alpha w}{|j\omega - s_1||j\omega - s_2|}\)</p>
<p>Phase: \(\Phi_R = \pi/2-\Phi(j\omega - s_1) -\Phi(j\omega - s_2)\)</p>
<p>Low-Pass Filter:</p>
<p>\(V_c(s) = I(s)/sC = \frac{1/LC}{s^2 + 2\alpha s + \omega_0^2}V_{in}(s) = \frac{\omega_0^2}{s^2 + 2\alpha s + \omega_0^2}V_{in}(s) = \frac{\omega_0^2}{(s-s_1)(s-s_2)}V_{in}(s)\)</p>
<p>Gain magnitude: \(G_C = \frac{\omega_0^2}{|j\omega - s_1||j\omega - s_2|}\)</p>
<p>Phase: \(\Phi_C = -\Phi(j\omega - s_1) -\Phi(j\omega - s_2)\)</p>
<p>High-Pass Filter:</p>
<p>\(V_l(s) = sLI(s) = \frac{s^2}{s^2 + 2\alpha s + \omega_0^2}V_{in}(s) = \frac{s^2}{(s-s_1)(s-s_2)}V_{in}(s)\)</p>
<p>Gain magnitude: \(G_L = \frac{\omega^2}{|j\omega - s_1||j\omega - s_2|}\)</p>
<p>Phase: \(\Phi_L = -\Phi(j\omega - s_1) -\Phi(j\omega - s_2)\)</p>
<br />
<p>Under-Damped: \(\alpha < \omega_0\)</p>
<p>Complex roots: \(s_{1,2} = -\alpha \pm j\sqrt{\omega_0^2 - \alpha^2}\)</p>
<p>Critically-Damped: \(\alpha = \omega_0\)</p>
<p>Double real root: \(s_{1,2} = -\alpha\)</p>
<p>Over-Damped: \(\alpha > \omega_0\)</p>
<p>Real roots: \(s_{1,2} = -\alpha \pm\sqrt{\alpha^2 - \omega_0^2}\)</p>
<endouttext />
</section>
<section class="tool-wrapper">
<div id="controlls-container">
<div class="graph-controls">
<div class="music-wrapper">
<select id="musicTypeSelect" size="1">
<option value = "0">Zero Input</option>
<option value = "1">Unit Impulse</option>
<option value = "2">Unit Step</option>
<option selected="selected" value = "3">Sine Wave</option>
<option value = "4">Square Wave</option>
<option value = "5">Classical Music</option>
<option value = "6">Folk Music</option>
<option value = "7">Jazz Music</option>
<option value = "8">Reggae Music</option>
</select>
<input id="playButton" type="button" value="Play" />
</div>
<div class="inputs-wrapper">
<div id="graph-output">
<p>Graph:</p>
<ul>
<li><label for="vinCheckbox"><input id="vinCheckbox" type="checkbox" checked="yes"/>v<sub>IN</sub></label></li>
<li><label for="vrCheckbox"><input id="vrCheckbox" type="checkbox"/>v<sub>R</sub></label></li>
<li><label for="vlCheckbox"><input id="vlCheckbox" type="checkbox"/>v<sub>L</sub></label></li>
<li><label for="vcCheckbox"><input id="vcCheckbox" type="checkbox" checked="yes"/>v<sub>C</sub></label> </li>
</ul>
</div>
<div id="graph-listen">
<p>Listen to:</p>
<ul>
<li><label for="vinRadioButton"><input id="vinRadioButton" type="radio" checked="yes" name="listenToWhat"/>v<sub>IN</sub></label></li>
<li><label for="vrRadioButton"><input id="vrRadioButton" type="radio" name="listenToWhat"/>v<sub>R</sub></label></li>
<li><label for="vlRadioButton"><input id="vlRadioButton" type="radio" name="listenToWhat"/>v<sub>L</sub></label></li>
<li><label for="vcRadioButton"><input id="vcRadioButton" type="radio" name="listenToWhat"/>v<sub>C</sub></label></li>
</ul>
</div>
</div>
</div>
<div class="schematic-sliders">
<div class="slider-label" id="vin"></div>
<div class="slider" id="vinSlider"></div>
<div class="slider-label" id="freq"></div>
<div class="slider" id="freqSlider"></div>
<div class="slider-label" id="vbias"></div>
<div class="slider" id="vbiasSlider"></div>
<div class="slider-label" id="r"></div>
<div class="slider" id="rSlider"></div>
<div class="slider-label" id="l"></div>
<div class="slider" id="lSlider"></div>
<div class="slider-label" id="c"></div>
<div class="slider" id="cSlider"></div>
<div class="slider-label" id="vc0"></div>
<div class="slider" id="vc0Slider"></div>
<div class="slider-label" id="i0"></div>
<div class="slider" id="i0Slider"></div>
<div class="slider-label" id="vmax"></div>
<div class="slider" id="vmaxSlider"></div>
</div>
</div>
<div id="graph-container">
<div id="graphTabs">
<ul>
<li><a href="#time">Time</a></li>
<li><a href="#magnitude">Magnitude</a></li>
<li><a href="#phase">Phase</a></li>
</ul>
<canvas id="time" width="500" height="500">Your browser must support the Canvas element and have JavaScript enabled to view this tool.</canvas>
<canvas id="magnitude" width="500" height="500">Your browser must support the Canvas element and have JavaScript enabled to view this tool.</canvas>
<canvas id="phase" width="500" height="500">Your browser must support the Canvas element and have JavaScript enabled to view this tool.</canvas>
</div>
<canvas id="diag3" width="500" height="500">Your browser must support the Canvas element and have JavaScript enabled to view this tool.</canvas>
</div>
</section>
common/test/data/full/html/test.html 0 → 100644
Test file for HTML in data
common/test/data/full/html/units_hint.html 0 → 100644
Hint
<br/><br/>
Be careful of units here. Make sure you notice multipliers such
as u, k, m, M.
common/test/data/full/info/guest_handouts.html 0 → 100644
<header>
<h1> Handouts </h1>
</header>
<ol class="treeview-handoutsnav">
<li> <a href="/static/handouts/syllabus.pdf"> Syllabus </a></li>
<li> <a href="/static/handouts/calendar.pdf"> 6.002x At-A-Glance (calendar) </a></li>
<li> <a href="/wiki/view/StaffListing"> Staff Listing </a></li>
<li> <a href="/wiki/view/MathReview"> Math Review </a></li>
<li> <a href="/static/handouts/schematic_tutorial.pdf"> Using the Interactive Laboratory </a></li>
<li> <a href="/static/handouts/SystemTools.pdf"> How to Use the System</a></li>
<li> <a href="/wiki/view/QuestionAnswerFAQ"> How to Use the Question/Answer forum </a></li>
<li>
<h4>Lecture Slides</h4>
<ul>
<li>
<h3>S1 - Administrivia and Circuit Elements</h3>
<p><a href="/static/handouts/6002-L1-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L1-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S2 - Circuit Analysis Toolchest</h3>
<p><a href="/static/handouts/6002-L2-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L2-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S3 - Linearity and Superposition</h3>
<p><a href="/static/handouts/6002-L3-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L3-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S4 - Static Discipline and Boolean Logic</h3>
<p><a href="/static/handouts/6002-L4-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L4-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S5 - Inside the Gate</h3>
<p><a href="/static/handouts/6002-L5-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L5-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S6 - Circuits with Nonlinear Elements</h3>
<p><a href="/static/handouts/6002-L6-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L6-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S7 - Incremental Analysis </h3>
<p><a href="/static/handouts/6002-L7-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L7-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S8 - Dependent Sources and Amplifiers </h3>
<p><a href="/static/handouts/6002-L8-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L8-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S9 - MOSFETs: Large Signals</h3>
<p><a href="/static/handouts/6002-L9-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L9-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S10 - MOSFET Amplifiers: Small Signal Model</h3>
<p><a href="/static/handouts/6002-L10-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L10-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S11 - Small-Signal Circuit Models</h3>
<p><a href="/static/handouts/6002-L11-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L11-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S12 - Capacitors and First-Order Circuits</h3>
<p><a href="/static/handouts/6002-L12-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L12-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S13 - Inductors and First-Order Circuits</h3>
<p><a href="/static/handouts/6002-L13-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L13-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S14 - Speed of Digital Circuits</h3>
<p><a href="/static/handouts/6002-L14-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L14-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S15 - Ramps, Steps, and Impulses</h3>
<p><a href="/static/handouts/6002-L15-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L15-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S16 - State and Memory</h3>
<p><a href="/static/handouts/6002-L16-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L16-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S17 - Undamped Second-Order Systems</h3>
<p><a href="/static/handouts/6002-L17-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L17-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S18 - Damped Second-Order Systems</h3>
<p><a href="/static/handouts/6002-L18-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L18-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S19 - Sinusoidal Steady State</h3>
<p><a href="/static/handouts/6002-L19-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L19-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S20 - The Impedance Model</h3>
<p><a href="/static/handouts/6002-L20-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L20-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S21 - Filters</h3>
<p><a href="/static/handouts/6002-L21-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L21-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S22 - Time Domain Versus Frequency Domain Analysis</h3>
<p><a href="/static/handouts/6002-L22-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L22-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S23 - The Operational Amplifier Abstraction</h3>
<p><a href="/static/handouts/6002-L23-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L23-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S24 - Operational Amplifier Circuits</h3>
<p><a href="/static/handouts/6002-L24-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L24-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
</ul>
</li>
</ol>
common/test/data/full/info/guest_updates.html 0 → 100644
<h1> Updates </h1>
<ol>
<li>
<section class="update-description">
Welcome to 6002x. Please look around.
</section>
</li>
</ol>
common/test/data/full/info/handouts.html 0 → 100644
<header>
<h1> Handouts </h1>
</header>
<ol class="treeview-handoutsnav">
<li> <a href="/static/handouts/syllabus.pdf"> Syllabus </a></li>
<li> <a href="/static/handouts/calendar.pdf"> 6.002x At-A-Glance (calendar) </a></li>
<li> <a href="/wiki/view/StaffListing"> Staff Listing </a></li>
<li> <a href="/wiki/view/MathReview"> Math Review </a></li>
<li> <a href="/static/handouts/schematic_tutorial.pdf"> Using the Interactive Laboratory </a></li>
<li> <a href="/static/handouts/SystemTools.pdf"> How to Use the System</a></li>
<li> <a href="/wiki/view/QuestionAnswerFAQ"> How to Use the Question/Answer forum </a></li>
<li>
<h4>Lecture Slides</h4>
<ul>
<li>
<h3>S1 - Administrivia and Circuit Elements</h3>
<p><a href="/static/handouts/6002-L1-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L1-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S2 - Circuit Analysis Toolchest</h3>
<p><a href="/static/handouts/6002-L2-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L2-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S3 - Linearity and Superposition</h3>
<p><a href="/static/handouts/6002-L3-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L3-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S4 - Static Discipline and Boolean Logic</h3>
<p><a href="/static/handouts/6002-L4-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L4-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S5 - Inside the Gate</h3>
<p><a href="/static/handouts/6002-L5-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L5-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S6 - Circuits with Nonlinear Elements</h3>
<p><a href="/static/handouts/6002-L6-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L6-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S7 - Incremental Analysis </h3>
<p><a href="/static/handouts/6002-L7-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L7-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S8 - Dependent Sources and Amplifiers </h3>
<p><a href="/static/handouts/6002-L8-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L8-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S9 - MOSFETs: Large Signals</h3>
<p><a href="/static/handouts/6002-L9-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L9-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S10 - MOSFET Amplifiers: Small Signal Model</h3>
<p><a href="/static/handouts/6002-L10-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L10-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S11 - Small-Signal Circuit Models</h3>
<p><a href="/static/handouts/6002-L11-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L11-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S12 - Capacitors and First-Order Circuits</h3>
<p><a href="/static/handouts/6002-L12-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L12-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S13 - Inductors and First-Order Circuits</h3>
<p><a href="/static/handouts/6002-L13-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L13-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S14 - Speed of Digital Circuits</h3>
<p><a href="/static/handouts/6002-L14-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L14-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S15 - Ramps, Steps, and Impulses</h3>
<p><a href="/static/handouts/6002-L15-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L15-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S16 - State and Memory</h3>
<p><a href="/static/handouts/6002-L16-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L16-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S17 - Undamped Second-Order Systems</h3>
<p><a href="/static/handouts/6002-L17-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L17-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S18 - Damped Second-Order Systems</h3>
<p><a href="/static/handouts/6002-L18-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L18-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S19 - Sinusoidal Steady State</h3>
<p><a href="/static/handouts/6002-L19-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L19-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S20 - The Impedance Model</h3>
<p><a href="/static/handouts/6002-L20-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L20-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S21 - Filters</h3>
<p><a href="/static/handouts/6002-L21-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L21-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
<li>
<h3>S22 - Time Domain Versus Frequency Domain Analysis</h3>
<p><a href="/static/handouts/6002-L22-oei12-gaps.pdf">Clean </a> <a href="/static/handouts/6002-L22-oei12-gaps-annotated.pdf">Annotated</a></p>
</li>
</ul>
</li>
<li>
<h4>Weekly solutions</h4>
<ul>
<li>
<h3>Week 1 Solutions</h3>
<p><a href="/static/handouts/solutions/Week1Ex.pdf">Exercises </a> <a href="/static/handouts/solutions/Week1HW.pdf">Homework</a> <a href="/static/handouts/solutions/Week1Lab.pdf">Lab</a></p>
</li>
<li>
<h3>Week 2 Solutions</h3>
<p><a href="/static/handouts/solutions/Week2Ex.pdf">Exercises </a> <a href="/static/handouts/solutions/Week2HW.pdf">Homework</a> <a href="/static/handouts/solutions/Week2Lab2B.pdf">Lab</a></p>
</li>
<li>
<h3>Week 3 Solutions</h3>
<p><a href="/static/handouts/solutions/Week3Ex.pdf">Exercises </a> <a href="/static/handouts/solutions/Week3HW.pdf">Homework</a> <a href="/static/handouts/solutions/Week3Lab.pdf">Lab</a></p>
</li>
<li>
<h3>Week 4 Solutions</h3>
<p><a href="/static/handouts/solutions/Week4Ex.pdf">Exercises </a> <a href="/static/handouts/solutions/Week4HW.pdf">Homework</a> <a href="/static/handouts/solutions/Week4Lab.pdf">Lab</a></p>
</li>
<li>
<h3>Week 5 Solutions</h3>
<p><a href="/static/handouts/solutions/Week5Ex.pdf">Exercises </a><a href="/static/handouts/solutions/Week5HW.pdf">Homework</a> <a href="/static/handouts/solutions/Week5Lab.pdf">Lab</a></p>
</li>
<li>
<h3>Week 6 Solutions</h3>
<p><a href="/static/handouts/solutions/Week6Ex.pdf">Exercises </a><a href="/static/handouts/solutions/Week6HW.pdf">Homework</a> <a href="/static/handouts/solutions/Week6Lab.pdf">Lab</a></p>
</li>
<li>
<h3>Week 7 Solutions</h3>
<p><a href="/static/handouts/solutions/Week7Ex.pdf">Exercises </a><a href="/static/handouts/solutions/Week7HW.pdf">Homework</a> <a href="/static/handouts/solutions/Week7Lab.pdf">Lab</a></p>
</li>
<li>
<h3>Week 8 Solutions</h3>
<p><a href="/static/handouts/solutions/Week8Ex.pdf">Exercises </a><a href="/static/handouts/solutions/Week8HW.pdf">Homework</a> <a href="/static/handouts/solutions/Week8Lab.pdf">Lab</a></p>
<li>
<h3>Week 9 Solutions</h3>
<p><a href="/static/handouts/solutions/Week9Ex.pdf">Exercises </a></p>
</li>
<li>
<h3>Week 10 Solutions</h3>
<p><a href="/static/handouts/solutions/Week10Ex.pdf">Exercises </a></p>
</li>
<li>
<h3>Week 11 Solutions</h3>
<p><a href="/static/handouts/solutions/Week11Ex.pdf">Exercises </a></p>
</li>
</ul>
</li>
<li>
<h3>Midterm Review Problems </h3>
<p><a href="/static/handouts/6002x-MidTermReview-S2012-clean.pdf">Clean </a> <a href="/static/handouts/6002x-MidTermReview-S2012.pdf">With Solutions</a></p>
</li>
<li> <a href="/static/handouts/solutions/Midterm.pdf"> Midterm Solutions </a></li>
</ol>
common/test/data/full/js/schematic.js 0 → 100644
This source diff could not be displayed because it is too large. You can view the blob instead.
common/test/data/full/problem/Circuit_Sandbox.xml 0 → 100644
<problem><startouttext/><p/>Here's a sandbox where you can experiment with all the components
we'll discuss in 6.002x. If you click on CHECK below, your diagram
will be saved on the server and you can return at some later time.
<endouttext/><schematicresponse><p/><center><schematic name="work" value="" width="800" height="600"/></center><answer type="loncapa/python">
correct = ['correct']
</answer></schematicresponse></problem>
common/test/data/full/problem/H1P1_Energy.xml 0 → 100644
<problem><script type="loncapa/python">
i = random.randrange(3)
M = ["Big Mac", "Angus Bacon and Cheese", "Quarter Pounder with Cheese"][i]
C = [540, 790, 510][i]
BM = C*1000*4.2
CB = 50*12*3600
</script><startouttext/>
According to McDonald's
<a href="http://nutrition.mcdonalds.com/getnutrition/nutritionfacts.pdf">nutrition
facts</a> a \($M\) provides \($C\) kiloCalories of energy. (1 dietitian's
calorie is 1000 physicist's calories.) A typical automobile lead-acid
battery can supply 50 Ampere-hours at 12 Volts. We can compare these by
converting the energy specifications to common units. The SI unit of
energy is the Joule=1 Watt-second. One physicist's calorie is 4.2 Joules.
<endouttext/>
<startouttext/>
<br/>
How many Joules are there in a \($M\)?
<endouttext/>
<numericalresponse answer="$BM"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
How many Joules are there in a car battery?
<endouttext/>
<numericalresponse answer="$CB"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
Which tastes better? :-)
<endouttext/>
</problem>
common/test/data/full/problem/H1P2_Duality.xml 0 → 100644
<problem><script type="loncapa/python">
scale = float(random.randrange(1000,2000,10))/1000
V = 10*scale
R1 = 3*scale
R2 = 2*scale
vV = V
R1R2S = R1+R2
i1 = V/R1R2S
i2 = i1
iV = -i1
v1 = i1*R1
v2 = i2*R2
Ps= vV*iV + v1*i1 + v2*i2
I = V
R3 = 1/R1
R4 = 1/R2
iI = -I
R3R4P = (R3*R4)/(R3+R4)
vI = I*R3R4P
v3 = vI
v4 = vI
i3 = v3/R3
i4 = v4/R4
Pp = vI*iI + v3*i3 + v4*i4
</script><startouttext/>
In this problem we will investigate a fun idea called "duality."
<br/>
Consider the series circuit in the diagram shown.
<center><img src="/static/circuits/duality.gif"/></center>
We are given device parameters \(V=$V\)V, \(R_1=$R1\Omega\), and \(R_2=$R2\Omega\).
All of the unknown voltages and currents are labeled in associated reference
directions. Solve this circuit for the unknowns and enter them into
the boxes given.
<br/>
The value (in Volts) of \(v_1\) is:
<endouttext/>
<numericalresponse answer="$v1"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
The value (in Amperes) of \(i_1\) is:
<endouttext/>
<numericalresponse answer="$i1"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
The value (in Volts) of \(v_2\) is:
<endouttext/>
<numericalresponse answer="$v2"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
The value (in Amperes) of \(i_2\) is:
<endouttext/>
<numericalresponse answer="$i2"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
The value (in Volts) of \(v_V\) is:
<endouttext/>
<numericalresponse answer="$vV"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
The value (in Amperes) of \(i_V\) is:
<endouttext/>
<numericalresponse answer="$iV"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
The sum of the powers (in Watts) entering all of the elements is:
<endouttext/>
<numericalresponse answer="$Ps"><responseparam type="tolerance" default="0.00001" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/> <br/> Now, let's turn our attentions to the parallel circuit.
The numerical value of the strength of the current source is set to be
the same as the numerical value of the strength of the voltage source:
\(I=$I\)A. The resistances are set to be reciprocals of the
resistances in the series circuit: \(R_3=$R3\Omega\) and
\(R_4=$R4\Omega\).
<br/>
Solve this circuit for the unknowns and enter them into
the boxes given.
<br/>
The value (in Volts) of \(v_3\) is:
<endouttext/>
<numericalresponse answer="$v3"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
The value (in Amperes) of \(i_3\) is:
<endouttext/>
<numericalresponse answer="$i3"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
The value (in Volts) of \(v_4\) is:
<endouttext/>
<numericalresponse answer="$v4"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
The value (in Amperes) of \(i_4\) is:
<endouttext/>
<numericalresponse answer="$i4"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
The value (in Volts) of \(v_I\) is:
<endouttext/>
<numericalresponse answer="$vI"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
The value of (in Amperes) \(i_I\) is:
<endouttext/>
<numericalresponse answer="$iI"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
The sum of the powers (in Watts) entering all of the elements is:
<endouttext/>
<numericalresponse answer="$Pp"><responseparam type="tolerance" default="0.00001" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/> <br/> Look carefully at the numbers you have derived.
Compare the series and parallel circuit. Do you see the pattern?
<endouttext/>
</problem>
common/test/data/full/problem/H1P3_Poor_Workmanship.xml 0 → 100644
<problem><script type="loncapa/python">
V = 240
P = float(random.randrange(800,1600,10))
Pmax = 3*P
Imax = Pmax/V
Iq = Pmax/120
R = (V**2)/P
Rbad = 3*R/2
Pbad = (V**2)/Rbad
Ibad = Pbad/V
PH1 = (Ibad**2)*R
PH2 = ((Ibad/2)**2)*R
PH3 = PH2
</script><startouttext/>
Joe wants to heat his 12'X20' workshop with electric heat. He has
hired the HACME electrician company to build the system. They propose
to use three \($P\)W 240V baseboard heaters to provide a total heating
capacity of \($Pmax\)W. (A heater is basically a
resistor. This is not quite true, because there is a thermostatic
switch incorporated into the heater and because the resistance of a
heater varies a bit with its temperature. But we will use a linear
resistor as a model of a heater.)
<br/>
In the proposed system the heaters are connected in parallel with the
240V 60Hz AC power line (modeled by a voltage source) as shown in the
diagram:
<center><img src="/static/circuits/heaters-parallel.gif"/></center>
Remember (from exercise S1E3: AC POWER) that AC power-line voltages
and currents are specified as RMS values. So 120V AC heats a given
resistance exactly as much as 120V DC would heat that same
resistance.
<endouttext/>
<startouttext/>
<br/>
How much current is expected to be drawn from the power line by this
heating system when all three heaters are on?
<endouttext/>
<numericalresponse answer="$Imax"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
If instead, HACME chose to implement the system with 120V heaters, how
much current would have been needed?
<endouttext/>
<numericalresponse answer="$Iq"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
Notice that this would require much heavier and more expensive wire to
distribute the power.
<br/> <br/>
Back to the original plan with 240V power.
<br/>
Unfortunately, Sparky, who works for HACME, was a little sleepy that
day. He accidentally connected the heaters as shown below:
<center><img src="/static/circuits/heaters-bad.gif"/></center>
<br/>
As a consequence, Joe found his workshop too cold. H1 was weak; H2
and H3 barely warmed up.
<br/>
What power was being dissipated in H1?
<endouttext/>
<numericalresponse answer="$PH1"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
What power was being dissipated in H2 (or in H3)?
<endouttext/>
<numericalresponse answer="$PH2"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
So the total heating power in Joe's shop was:
<endouttext/>
<numericalresponse answer="$Pbad"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/>
No wonder Joe was cold.
<endouttext/>
</problem>
common/test/data/full/problem/Lab_0_Using_the_Tools.xml 0 → 100644
<problem><startouttext/><br/>In this first lab, the goal is to familiarize yourself with the
interactive tool that will be used to enter and analyze circuits. Here's
the example schematic used below:
<br/><center><input type="hidden" class="schematic" analyses="" parts="" origin_x="50" origin_y="20" width="400" height="350" name="fig1" value="[[&quot;w&quot;,[120,160,144,160]],[&quot;v&quot;,[48,64,0],{&quot;name&quot;:&quot;Vsupply&quot;,&quot;value&quot;:&quot;dc(3)&quot;,&quot;_json_&quot;:1},[&quot;A&quot;,&quot;D&quot;]],[&quot;r&quot;,[120,64,0],{&quot;name&quot;:&quot;R2&quot;,&quot;r&quot;:&quot;3k&quot;,&quot;_json_&quot;:2},[&quot;B&quot;,&quot;C&quot;]],[&quot;r&quot;,[120,16,0],{&quot;name&quot;:&quot;R1&quot;,&quot;r&quot;:&quot;1k&quot;,&quot;_json_&quot;:3},[&quot;A&quot;,&quot;B&quot;]],[&quot;r&quot;,[120,112,0],{&quot;name&quot;:&quot;R3&quot;,&quot;r&quot;:&quot;2k&quot;,&quot;_json_&quot;:4},[&quot;C&quot;,&quot;D&quot;]],[&quot;w&quot;,[48,64,48,16]],[&quot;w&quot;,[48,16,120,16]],[&quot;w&quot;,[48,112,48,160]],[&quot;w&quot;,[48,160,120,160]],[&quot;w&quot;,[120,112,144,112]],[&quot;w&quot;,[120,64,144,64]],[&quot;w&quot;,[120,16,144,16]],[&quot;L&quot;,[144,16,3],{&quot;label&quot;:&quot;A&quot;,&quot;_json_&quot;:12},[&quot;A&quot;]],[&quot;L&quot;,[144,64,3],{&quot;label&quot;:&quot;B&quot;,&quot;_json_&quot;:13},[&quot;B&quot;]],[&quot;L&quot;,[144,112,3],{&quot;label&quot;:&quot;C&quot;,&quot;_json_&quot;:14},[&quot;C&quot;]],[&quot;g&quot;,[48,160,0],{&quot;_json_&quot;:15},[&quot;D&quot;]],[&quot;L&quot;,[144,160,3],{&quot;label&quot;:&quot;D&quot;,&quot;_json_&quot;:16},[&quot;D&quot;]],[&quot;view&quot;,0,0,2,&quot;5&quot;,&quot;10&quot;,&quot;10MEG&quot;,null,&quot;100&quot;,&quot;1&quot;]]"/>
Figure 1. Test Circuit for Lab 0
</center><br/>And here's the interactive tool to be used in the tasks that follow:
<endouttext/><schematicresponse><startouttext/><br/><center><schematic analyses="dc,tran" parts="g,L,v,r,s" name="work" value="" width="600" height="400"/></center><endouttext/><answer type="loncapa/python">
correct = ['correct']
</answer></schematicresponse><startouttext/><br/>Please do the following tasks. When you're done, remember to click CHECK to preserve
your work and to verify your answers.
<ol style="list-style-type:decimal; margin-left: 2em;"><br/><li><b>Enter schematic.</b> Add the voltage source, resistors,
wires and ground reference to your diagram, connected as shown
in <nobr>Figure 1</nobr>.</li><br/><li><b>Measure voltages.</b> Use the tool to run a DC analysis on
the circuit, i.e.., click on the DC button in the toolbar. This will
annotate each node/voltage source in the circuit with a
voltage/current. If the components are wired correctly, the
voltage for node D should be reported as 0V since it's
connected to the ground reference and the voltage for node A
should be reported as 3V since it is connected directly to the
positive terminal of a 3V voltage source whose negative terminal
is connected to ground. Please enter the voltages reported for nodes
B and C.
<br/><div style="margin-left: 4em;">
Voltage for node B (volts):
<numericalresponse answer="2.5"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
</div>
<div style="margin-left: 4em;">
Voltage for node C (volts):
<numericalresponse answer="1.0"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
</div>
</li><br/><li><b>Measure current.</b>
The DC analysis annotates each voltage source with the current it is
providing to the rest of the circuit. The simulator denotes the sign
of the source current as positive if the current is flowing out of the
positive terminal of the source, through the rest of the circuit, and
then back in to the negative terminal. And the source current sign is
negative if the current is flowing out of the negative terminal of the
source, through the circuit, and into the positive terminal of the
source. Please report the total resistance of the path connecting the
positive and negative terminals of the source, the signed current
flowing from the source into the circuit, and (using the voltage
value for the source) verify that Ohm's law is obeyed.
<br/><div style="margin-left: 4em;">
Total resistance between pos and neg terminals (ohms):
<numericalresponse answer="6000"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
</div>
<div style="margin-left: 4em;">
Current flowing from source into the circuit (amps, with correct sign):
<numericalresponse answer="500e-6"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
</div>
</li><br/><li><b>Verify KVL.</b> The four components in the schematic form a
large loop -- let's verify that Kirchoff's Voltage Law holds by
summing the voltage changes across the devices. Starting with node A,
travel clockwise around the loop of components, entering the voltage
change across each component. Choose the sign of the change for a
component using the first terminal you come to in the clockwise
traversal as the reference node. Verify that these four values sum
to 0.
<br/>
<div style="margin-left: 4em;">
Voltage change across R1 (volts, with correct sign):
<numericalresponse answer="-0.5"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
</div>
<div style="margin-left: 4em;">
Voltage change across R2 (volts, with correct sign):
<numericalresponse answer="-1.5"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
</div>
<div style="margin-left: 4em;">
Voltage change across R3 (volts, with correct sign):
<numericalresponse answer="-1.0"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
</div>
<div style="margin-left: 4em;">
Voltage change across Vsupply (volts, with correct sign):
<numericalresponse answer="3.0"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
</div>
</li><br/><li><b>Transient analysis.</b> Change the waveform produced by
the voltage source from a DC value of 3V to a sinusoid with a 1V
amplitude, an offset voltage of 1V, and a frequency of 1kHz. Add
scope probes to nodes A, B and C and edit their properties so that the
plots will be different colors. Now run a transient analysis for 5ms.
Move the mouse over the plot until the marker (a vertical dashed line
that follows the mouse when it's over the plot) is at approximately
1.25ms. Please report the measured voltages for nodes A, B and C.
<br/>
<div style="margin-left: 4em;">
Voltage for node A (volts):
<numericalresponse answer="1.995"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
</div>
<div style="margin-left: 4em;">
Voltage for node B (volts):
<numericalresponse answer="1.662"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
</div>
<div style="margin-left: 4em;">
Voltage for node C (volts):
<numericalresponse answer=".665"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
</div>
</li></ol><endouttext/></problem>
common/test/data/full/problem/Resistor_Divider.xml 0 → 100644
<problem><startouttext/><br/><br/>You have a 6-volt battery (assumed ideal) and a 1.5-volt flashlight
bulb, which is known to draw \(0.5 A\) when the bulb voltage is \(1.5 V\) (see
figure below). Design a network of resistors to go between the battery
and the bulb to give \(v_s = 1.5 V\) when the bulb is connected, yet
ensures that \(v_s\) does not rise above \(2 V\) when the bulb is disconnected.
<br/><br/><center><img src="/static/circuits/Lab1_1.png"/></center><br/><br/><i>Hint</i>: use a two-resistor voltage divider to create the voltage for node A. You'll
have two unknowns (R1 and R2) which can be determined by solving the two equations for
\(v_s\) derived from the constraints above: one involving R1, R2 and Rbulb where \(v_s = 1.5\), and
one involving R1 and R2 where \(v_s = 2\).
<br/><br/>There are two schematic diagrams below. Please enter the network
of resistors you've designed into both diagrams. The top diagram is
the model when the bulb is connected; the bottom diagram is the model
when the bulb is disconnected.
<br/><br/>Run a DC analysis on both diagrams to
show that the node labeled "A" has a voltage of approximately
\(1.5 V\) in the top diagram and less than \(2 V\) in the bottom
adiagram. Submit your results <i>after</i> the DC analyses have
been run (so the results of the analyses will be submitted too).
<endouttext/>
<schematicresponse><startouttext/>
Schematic model when bulb is connected:
<center><schematic height="270" width="400" parts="r" analyses="dc" initial_value="[[&quot;w&quot;,[48,88,48,112]],[&quot;L&quot;,[160,16,3],{&quot;label&quot;:&quot;A&quot;},[&quot;A&quot;]],[&quot;g&quot;,[48,112,0],{},[&quot;0&quot;]],[&quot;w&quot;,[160,112,136,112]],[&quot;w&quot;,[160,88,160,112]],[&quot;w&quot;,[160,16,136,16]],[&quot;w&quot;,[160,40,160,16]],[&quot;r&quot;,[160,40,0],{&quot;name&quot;:&quot;Bulb&quot;,&quot;r&quot;:&quot;3&quot;},[&quot;A&quot;,&quot;1&quot;]],[&quot;w&quot;,[48,112,72,112]],[&quot;w&quot;,[48,16,72,16]],[&quot;w&quot;,[48,40,48,16]],[&quot;v&quot;,[48,40,0],{&quot;name&quot;:&quot;Battery&quot;,&quot;value&quot;:&quot;6V&quot;},[&quot;2&quot;,&quot;0&quot;]],[&quot;view&quot;,0,0,2]]"/></center>
Schematic model when bulb is disconnected:
<center><schematic height="270" width="400" parts="r" analyses="dc" initial_value="[[&quot;w&quot;,[48,88,48,112]],[&quot;L&quot;,[160,16,3],{&quot;label&quot;:&quot;A&quot;},[&quot;A&quot;]],[&quot;g&quot;,[48,112,0],{},[&quot;0&quot;]],[&quot;w&quot;,[160,112,136,112]],[&quot;w&quot;,[160,88,160,112]],[&quot;w&quot;,[160,16,136,16]],[&quot;w&quot;,[160,40,160,16]],[&quot;w&quot;,[48,112,72,112]],[&quot;w&quot;,[48,16,72,16]],[&quot;w&quot;,[48,40,48,16]],[&quot;v&quot;,[48,40,0],{&quot;name&quot;:&quot;Battery&quot;,&quot;value&quot;:&quot;6V&quot;},[&quot;2&quot;,&quot;0&quot;]],[&quot;view&quot;,0,0,2]]"/></center>
<endouttext/>
<answer type="loncapa/python">
# for a schematic response, submission[i] is the json representation
# of the diagram and analysis results for the i-th schematic tag
correct = ['incorrect', 'incorrect'] # optimistic default :)
def get_dc(json):
for element in json:
if element[0] == 'dc': return element[1]
return None
dc_with_bulb = get_dc(submission[0])
if dc_with_bulb:
v = dc_with_bulb['A']
if v &gt;= 1.4 and v &lt;= 1.6: # want 1.5
correct[0] = 'correct'
dc_without_bulb = get_dc(submission[1])
if dc_without_bulb:
v = dc_without_bulb['A']
if v &lt;= 2.1: # want 2
correct[1] = 'correct'
</answer>
</schematicresponse>
</problem>
common/test/data/full/problem/S1E3_AC_power.xml 0 → 100644
<problem><script type="loncapa/python">
R = float(random.randrange(100,200,10))
Vrms = 120
Vp = math.sqrt(2)*Vrms
Pp = (Vp**2)/R
Prms = (Vrms**2)/R
</script><startouttext/>
The plot shows 1/10 second of the voltage waveform of a 120V 60Hz AC
(Alternating Current)
power circuit, like that delivered to residences in the United States.
<center><img src="/static/circuits/120V60Hz.gif"/></center>
The actual voltage is \(120*sqrt(2)*cos(2*\pi*60*t)\)Volts. If we apply
this voltage across a resistor of resistance \($R\Omega\) the resistor
will dissipate a time-varying power.
What is the peak power (in Watts) dissipated by the resistor?
<endouttext/>
<numericalresponse answer="$Pp"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/> What is the average power (in Watts) dissipated by the resistor? (Hint: you
compute the average power by integrating the power over one cycle of
the waveform.)
<endouttext/>
<numericalresponse answer="$Prms"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/> What would be the power (in Watts) dissipated by the resistor if the voltage
was a constant value of 120V?
<endouttext/>
<numericalresponse answer="$Prms"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
<startouttext/>
<br/> If a time-varying voltage dissipates the same power in a resistor
as a constant voltage would dissipate, we say that the time-varying voltage has
the RMS value of the constant. RMS is an abbreviation for Root-Mean-Square.
<endouttext/>
</problem>
common/test/data/full/problem/Sample_Algebraic_Problem.xml 0 → 100644
<problem><script type="loncapa/python">
z = "A*x^2 + sqrt(y)"
</script><startouttext/>
Enter the algebraic expression \(A x^2 + \sqrt{y}\) in the box below. The
entry is case sensitive. The product must be indicated with an
asterisk, and the exponentation with a caret, so you must write
"A*x^2 + sqrt(y)".
<endouttext/>
<formularesponse type="cs" samples="A,x,y@1,1,1:3,3,3#10" answer="$z"><responseparam description="Numerical Tolerance" type="tolerance" default="0.00001" name="tol"/><textline size="40"/></formularesponse>
</problem>
common/test/data/full/problem/Sample_Numeric_Problem.xml 0 → 100644
<problem><startouttext/>
Enter the numerical value of the expression \(x + y\) where
\(x = 3\) and \(y = 5\).
<endouttext/>
<numericalresponse answer="8"><responseparam type="tolerance" default="5%" name="tol" description="Numerical Tolerance"/><textline/></numericalresponse>
</problem>
common/test/data/full/sequential/Administrivia_and_Circuit_Elements.xml 0 → 100644
<sequential>
<vertical filename="vertical_58" slug="vertical_58" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never"/>
<vertical slug="vertical_66" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never">
<problem filename="S1E3_AC_power" slug="S1E3_AC_power" name="S1E3: AC power"/>
<customtag tag="S1E3" slug="discuss_67">
<impl>discuss</impl>
</customtag>
<html slug="html_68"> S1E4 has been removed. </html>
</vertical>
<vertical filename="vertical_89" slug="vertical_89" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never"/>
<vertical slug="vertical_94" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never">
<video youtube="0.75:XNh13VZhThQ,1.0:XbDRmF6J0K0,1.25:JDty12WEQWk,1.50:wELKGj-5iyM" slug="What_s_next" name="What's next"/>
<html slug="html_95">Minor correction: Six elements (five resistors)</html>
<customtag tag="S1" slug="discuss_96">
<impl>discuss</impl>
</customtag>
</vertical>
</sequential>
common/test/data/full/sequential/System_Usage_Sequence.xml 0 → 100644
<sequential>
<vertical slug="vertical_7" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never">
<problem filename="Sample_Numeric_Problem" slug="Sample_Numeric_Problem" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="false" name="Sample Numeric Problem"/>
<problem filename="Sample_Algebraic_Problem" slug="Sample_Algebraic_Problem" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="false" name="Sample Algebraic Problem"/>
</vertical>
<vertical filename="vertical_16" slug="vertical_16" graceperiod="1 day 12 hours 59 minutes 59 seconds" showanswer="attempted" rerandomize="never"/>
</sequential>
common/test/data/full/subs/3NIegrCmA5k.srt.sjson 0 → 100644
{
"start": [],
"end": [],
"text": []
}
\ No newline at end of file
common/test/data/full/subs/4cLA-IME32w.srt.sjson 0 → 100644
{
"start": [],
"end": [],
"text": []
}
\ No newline at end of file
common/test/data/full/subs/8kARlsUt9lM.srt.sjson 0 → 100644
{
"start": [],
"end": [],
"text": []
}
\ No newline at end of file
common/test/data/full/subs/8rK9vnpystQ.srt.sjson 0 → 100644
{
"start": [],
"end": [],
"text": []
}
\ No newline at end of file
common/test/data/full/subs/BGU1poJDgOY.srt.sjson 0 → 100644
{
"start": [
0,
410,
2390,
5510,
7110,
10400,
13120,
15150,
18850,
20800,
25570,
27950,
32870,
36560,
38920,
40850,
43130,
46690,
48640,
50910,
54260,
56872,
59590,
63370,
66290,
68000,
71320,
74130,
77880,
80860,
81900,
85380,
89890,
93550,
97980,
100960,
104010,
105450,
107320,
110600,
114310,
116940,
118800,
122550,
124950,
127000,
129479,
131740,
133570,
137170,
141410,
143740,
146820,
148870,
152620,
157640,
162970,
164060,
167630,
168680,
171890,
173700,
177560,
181850,
185390,
189290,
191550,
196470,
197780,
202150,
204550,
208200,
210910,
213870,
218830,
222090,
225070,
229290,
233580,
236700,
239510,
242110,
243770,
246990,
247950,
251740,
255340,
256500,
258759
],
"end": [
410,
2390,
5510,
7109,
10400,
13120,
15149,
18850,
20800,
25570,
27950,
32870,
36559,
38920,
40850,
43130,
46690,
48640,
50910,
54260,
56872,
59590,
63370,
66289,
68000,
71320,
74130,
77880,
80860,
81900,
85380,
89890,
93550,
97979,
100960,
104009,
105450,
107320,
110600,
114309,
116940,
118800,
122550,
124950,
127000,
129479,
131740,
133570,
137170,
141410,
143740,
146820,
148870,
152620,
157640,
162970,
164060,
167630,
168680,
171890,
173700,
177560,
181850,
185390,
189290,
191549,
196470,
197780,
202150,
204550,
208200,
210910,
213870,
218830,
222090,
225070,
229290,
233579,
236700,
239510,
242109,
243770,
246990,
247950,
251739,
255340,
256500,
258759,
260009
],
"text": [
null,
"Let us summarize what we&#39;ve\nlearned so far.",
"So we started out with building\nthis playground, this",
"EECS playground.",
"And within this playground,\nwe&#39;ve all decided that we will",
"abide by the lumped matter\ndiscipline, the LMD.",
"And these are simply constraints\nthat we impose",
"upon ourselves to simplify\nour analysis.",
"Notice that, you really\ndon&#39;t have to do that.",
"You are welcome to hang out here\nand do whatever you want.",
"But you might have a\nlot of fun as well.",
"But, you will not be able to\nbuild things as simply as you",
"would if you were inside\nthe EECS playground.",
"But, Within this playground\nyou have promised that you",
"will follow the lumped\nmatter discipline.",
"Lumped matter discipline has\nthree components to it.",
"One is that the elements will\nhave del phi b by del t equals",
"zero, outside the elements.",
"In other words, when you build\ncircuits, you want to make",
"sure that the del phi b by del\nt is going to be zero.",
"And inside the elements, we are\ngoing to make sure that",
"when you define something--\ndescribe something as a lumped",
"element, del q by del t,\nfor that element--",
"the net del q by del t for\nthat element inside the",
"element is going to be zero.",
"And that&#39;s going to be true\nfor all your elements,",
"registers, sources,\nwires, and so on.",
"And the third element is that\nyou will only focus on signal",
"speeds of interest that\nwill be way lower than",
"the speed of light.",
"Now one of the interesting facts\nof life is that as our",
"microprocessors get faster and\nfaster, some of the chips",
"inside your iPhones, and your\ndesktops, and so on, are",
"clocking at speeds in excess\nof three to four gigahertz.",
"When signal speeds are that\nfast, we are now getting to a",
"point where the signal speeds\ninside our chips are",
"approaching the speed\nof light.",
"So they&#39;re not all\nthat far off.",
"And so therefore, over the next\ndecade, as people try to",
"push speeds to even higher\nvalues, various things are",
"going to start breaking unless\nwe change things",
"dramatically somehow.",
"What this does is these\ndiscipline elements, the",
"lumped matter discipline,\nenables us to create the",
"lumped circuit abstraction.",
"Look at our lumped elements.",
"Lumped elements will\nbe described",
"by their v-i relation.",
"So each of these lumped elements\nof that sum i, that",
"would be sum function of\nv, the v-i relation.",
"The relation could be linear,\ncould be non-linear.",
"Could be, in general, could be\nanything, just that they have",
"some v-i relation.",
"For the register you saw that\ni was v divided by R.",
"For some other element, it could\nbe that i is 6.7 times v",
"squared plus v divided by\n2 plus some constant 1.",
"I mean, who knows.",
"That could be some function of\nv. Could be linear, could be",
"non-linear.",
"And for this element, the power\nconsumed by the element",
"is given by vi.",
"Finally, we showed that when\nyou make the lumped matter",
"discipline assumptions,\nMaxwell&#39;s equations simplify",
"to extremely simple\nKVL and KCL.",
"So, for example, KVL simply\nsays that the sum of the",
"voltages around a\nloop is zero.",
"While KCL says that the sum of\nthe current that go into a",
"node is zero.",
"You can also say the currents\ncoming out of a node are zero",
"by the same principle.",
"What is amazing about this is\nthat by making the lumped",
"matter discipline, by abiding\nby the lumped matter",
"discipline, we have been able\nto convert the use of",
"Maxwell&#39;s equation into the use\nof very simple algebra.",
"So we replaced our del phi&#39;s and\ndel t&#39;s, and all of that",
"stuff, with extremely\nsimple algebra.",
"And in the next set of segments\nI&#39;m going to show you",
"how we can simplify and analyze\ncircuits extremely",
"easily using very, very\nsimple algebra.",
"And, in fact, for the first half\nof this course, you are",
"not going to see any\nsquigglies at all.",
"It&#39;s going to be very,\nvery simple.",
"And even later, we&#39;re not going\nto be seeing any partial",
"differential equations.",
"We will see some fairly simple\ndifferential equations, but by",
"making the LMD assumptions, we\nhave really gotten rid of a",
"lot of the complexity.",
"And things are going to be\nreally, really, really simple.",
null
]
}
\ No newline at end of file
common/test/data/full/subs/CcgAYu0n0bg.srt.sjson 0 → 100644
{
"start": [],
"end": [],
"text": []
}
\ No newline at end of file
common/test/data/full/subs/EG-fRTJln_E.srt.sjson 0 → 100644
{
"start": [],
"end": [],
"text": []
}
\ No newline at end of file
common/test/data/full/subs/G_2F9wivspM.srt.sjson 0 → 100644
{
"start": [
0,
1800,
2440,
7270,
11690,
13030,
17060,
21240,
24980,
29930,
33740,
37930,
40340,
46830,
50200,
52890,
56355,
59450,
60430,
66640,
69640,
72148,
73398,
77730,
83080,
84330,
99630,
103660,
110800,
114250,
118220,
121940,
131580,
134300,
137730,
140540,
143860,
146050,
147300,
149850,
157140,
161820,
164460,
165600,
169520,
174040,
176290,
178310,
181070,
182920,
184160,
189960,
192630,
193480,
199020,
201540,
204520,
208180,
211470,
217120,
220790,
224490,
227200,
229150,
232940,
236320,
239070,
242480
],
"end": [
1800,
2440,
7270,
11690,
13030,
17060,
21240,
24979,
29930,
33740,
37930,
40340,
46830,
50199,
52890,
56355,
59449,
60430,
66640,
69640,
72148,
73398,
77729,
83080,
84330,
99630,
103660,
110800,
114250,
118220,
121940,
131579,
134300,
137730,
140540,
143859,
146050,
147300,
149850,
157140,
161820,
164459,
165600,
169519,
174040,
176290,
178310,
181070,
182920,
184160,
189960,
192630,
193480,
199019,
201540,
204519,
208180,
211470,
217120,
220790,
224489,
227200,
229149,
232940,
236320,
239070,
242480,
243730
],
"text": [
"SPEAKER 1: So I want to show\nyou a simple circuit that",
"looks like this.",
"And let&#39;s go ahead and measure\nsome voltages and currents.",
"In terms of terminology,\nremember",
"this is called a loop.",
"So if I start from the point\nC, and I travel through the",
"voltage source, come to the node\nA, down through R1 and",
"all the way down through R2\nback to C, that&#39;s a loop.",
"Similarly, this point A is a\nnode where the register R1,",
"the voltage source V0 and\nR4 are connected.",
"Just make sure your terminology\nis correct.",
"So what I&#39;ll do is let me make\nsome quick measurements for",
"you, and show you that these KVL\nand KCL are indeed true.",
"So the circuit&#39;s up there.",
"So let me take some\nmeasurements.",
"And why don&#39;t you write down\nwhat I measure on the board.",
null,
"Let me borrow another\npiece of chalk here.",
"What I&#39;ll do is focus on this\nloop here and focus on this",
"node and make some\nmeasurements.",
"So you see the circuit\nup there.",
"[INAUDIBLE]",
null,
"So I get three volts for the\nvoltage from C to A. So why",
"don&#39;t you write down\nthree volts.",
null,
"OK, so the next one\nis minus 1.6.",
null,
"And so that will be\nI&#39;m doing AB, VAB.",
null,
"And then let me do\nthe last one.",
"And it is minus 1.37.",
"Within the bonds of experimental\nerror, notice",
"that if I add up these\nthree voltages, they",
"nicely sum up to zero.",
"OK, next let me focus\non this node here.",
"And at this node, let\nme go ahead and",
"measure some currents.",
null,
"What I&#39;ll do now is change to an\nAC voltage so that I can go",
"ahead and measure the current\nwithout breaking my circuit.",
"This time around, you&#39;ll get to\nsee the measurements that",
"I&#39;m taking as well.",
"What I have here is three wires\nthat I have pulled out",
"from D. And this is the node D.\nSo three wires coming into",
"the node D just to make it a\nlittle bit easier for me to",
"measure stuff.",
"So everybody keep your fingers\ncrossed so I don&#39;t",
"look like a fool here.",
"Hope this works out.",
"So it&#39;s about 10 millivolts\npeak to peak out there.",
"Let&#39;s say that if the wave form\nrises on the left hand",
"side, it&#39;s positive.",
"So it&#39;s positive\n10 millivolts.",
"And another positive\n10 millivolts.",
"So that&#39;s 20 millivolts.",
"And this time it&#39;s a negative,\nroughly 20, I",
"guess, negative 20.",
"So I&#39;m getting, in terms of\ncurrents, I have a positive",
"10, a positive 10 and a negative\n20 that adds up to 0.",
"But more interestingly, I can\nshow you the same thing by",
"holding this current\nmeasuring probe",
"directly across that node.",
"And notice that the net current\nthat is entering into",
"this node here is zero.",
"So that should just show you\nthat KCL does indeed hold in",
"practice, and it is not just a\nfigment of our imaginations.",
null
]
}
\ No newline at end of file
common/test/data/full/subs/XbDRmF6J0K0.srt.sjson 0 → 100644
{
"start": [
0,
3780,
5290,
9590,
13370,
13735,
15275,
16740,
19790,
23420,
26470,
28560,
31630,
33770,
35320,
36750,
38390,
41660,
43720,
46740,
47805,
49920,
52170,
53540,
56530,
59350,
63350,
66470,
68440,
69220,
71320,
72870,
78300,
79890,
82470,
85670,
90720,
93660,
97005,
98280,
102090,
103460,
107090,
108040,
110700,
112510,
117400,
121890,
124450,
130229,
133180,
140010,
142500,
143580,
150010,
152720,
159180,
161330,
165510,
171270,
173750,
177000,
179340,
181273,
182400,
188140,
189210,
192730,
199620,
206460,
208220,
211810,
214510,
219790,
221440,
223910,
224950,
226060,
231860,
232940,
237990,
240450,
242470,
244760,
246470,
248420
],
"end": [
3780,
5290,
9590,
13370,
13735,
15275,
16740,
19790,
23420,
26470,
28560,
31630,
33770,
35320,
36750,
38390,
41660,
43720,
46740,
47805,
49920,
52170,
53540,
56530,
59350,
63350,
66470,
68440,
69220,
71320,
72870,
78300,
79890,
82470,
85670,
90720,
93660,
97005,
98280,
102090,
103460,
107090,
108040,
110700,
112510,
117400,
121890,
124450,
130229,
133180,
140010,
142500,
143580,
150010,
152720,
159180,
161330,
165510,
171270,
173750,
177000,
179340,
181273,
182400,
188140,
189210,
192730,
196700,
206460,
208220,
211810,
214510,
219790,
221440,
223910,
224950,
226060,
231860,
232940,
237990,
240450,
242470,
244760,
246470,
248420,
249670
],
"text": [
"SPEAKER 1: We just learned the fundamental rules of",
"electrical circuits.",
"For example, if we have a circuit like this, which is",
"called a bridge and which has a voltage source and five",
"resistors--",
"SPEAKER 2: And I'll show the circuit in lecture.",
"SPEAKER 1: That's right.",
"We had a bunch of voltage current constraints, one for",
"each of the branches, each of the elements in the network.",
"For example, this one, the voltage across it is the",
"voltage intrinsic to it.",
"And we have Kirchoff's Current Laws, one for each of the",
"possible nodes in the network.",
"So that's four of them here.",
"It turns out one of them is redundant.",
"It can be derived from the others.",
"And we have Kirchoff Voltage Laws, which are some of the",
"voltages around the loop is zero.",
"And I have four of them written down here, and only",
"three of them are independent.",
"But we can have many more because there's a loop I",
"didn't show, which is the one that looks like this, for",
"example, OK?",
"And the other thing we have is that some of the powers on the",
"network entering each the elements is zero.",
"So there's no power gained or lost. This is a general method",
"of solving all circuit problems. Unfortunately, even",
"for a simple circuit like this, we have a mess of",
"equations here.",
"This is not a good idea.",
"SPEAKER 2: So in the next lecture, what Anant will show",
"you is a much more coherent, a much better organized",
"technique for solving these circuits.",
"So again, if we circle this circuit--",
"this is the same brood circuit Anant showed in the lecture--",
"we have six resistors, one, two, three, four nodes.",
"And what we do is we take each of these nodes and for those",
"nodes we'll write Kirchoff's Current Law.",
"And that's called nodal analysis.",
"So step zero is we pick one of these nodes and we label that",
"node as ground.",
"And labeling it ground just says the voltage on",
"that node is zero.",
"SPEAKER 1: The potential on that node is zero.",
"Voltages are differences of potential.",
"SPEAKER 2: Then we take a node, such as b.",
"And for that node, b, we write down an equation that says the",
"currents going into that node are o0.",
"So IR1 is plus IR2 plus IR3 is equal to zero.",
"We take this node, d, where we also write down Kirchoff's",
"Current Law, IR3 plus IR4 plus IR5 is equal to zero.",
"And at that point, we substitute",
"in for those voltages.",
"So when we have IR3, that's just b minus d over R3.",
"That's the current going into it.",
"For R5 over here, we have just d--",
"IS is 0 minus d.",
"So that's just minus d over R5.",
"And for IR4, we have a minus d over R4.",
"So we have an equation like this.",
"SPEAKER 1: So these labels, a, b and d, are within node",
"potentials, OK?",
"SPEAKER 2: We do the same thing over here for--",
"SPEAKER 1: Right, yes.",
"SPEAKER 2: We do the same thing over here for IR2 is--",
"SPEAKER 1: It's IR1.",
"SPEAKER 2: IR1 is a minus b over R1.",
"IR3 is d minus b over R3.",
"And finally, IR2 is minus b over R2.",
"So now we have two equations.",
"And the last thing that we do is we label this node a to",
"have the voltage v. We say a is equal to v.",
"Since this is a zero, instead of a, it's v, we make that",
"substitution everywhere here.",
"We have two equations, two unknowns.",
"We solve it.",
"And that gives us our answer.",
"SPEAKER 1: So the equations are b and d because all the",
"A's are substituted for.",
"And all of the KCLs that were written with the KCLs for some",
"of the currents entering the node is zero.",
"You could have equally written them as some of the currents",
"leaving the node as zero and get the same answer because",
"that would just multiply everything by minus 1.",
"SPEAKER 2: So you'll see this next week.",
"That's just a preview of coming attractions."
]
}
\ No newline at end of file
common/test/data/full/subs/eLAyO33baQ8.srt.sjson 0 → 100644
{
"start": [
0,
430,
3070,
5680,
9120,
12590,
13280,
17280,
20200,
23630,
26720,
29450,
32700,
35920,
39280,
43310,
44850,
46400,
48270,
52110,
54140,
57570,
61600,
63040,
64410,
66980,
69920,
72490,
75110,
77540,
80680,
84430,
87190,
91790,
94420,
97830,
101030,
104180,
106960,
108320,
110885,
113180,
115630,
119930,
122740,
129590,
131000,
134200,
138470,
142200,
145410,
150500,
153590,
158000,
160290,
164600,
167370,
169272,
173420,
176650,
180460,
183390,
185200,
188940,
190750,
194040,
196510,
198060,
202670,
206860,
209980,
213620,
219130,
221760,
222700,
227050,
230340,
234810,
236930,
239030,
241390,
246630,
248200,
252220,
255370,
257160,
258709,
263370,
264280,
266840,
270190,
275640,
277790,
280880,
282680,
283930,
285990,
287870,
290740,
294140,
299760,
305270,
308230,
310160,
311540,
314150,
316160,
316440,
318500
],
"end": [
430,
3070,
5680,
9120,
12590,
13280,
17280,
20200,
23630,
26720,
29450,
32700,
35920,
39280,
43310,
44850,
46400,
48269,
52110,
54140,
57570,
61600,
63040,
64410,
66979,
69920,
72490,
75110,
77540,
80680,
84430,
87190,
91789,
94420,
97830,
101030,
104180,
106960,
108320,
110884,
113180,
115630,
119929,
122740,
129590,
131000,
134200,
138470,
142200,
145410,
150500,
153590,
158000,
160290,
164600,
167370,
169272,
173420,
176649,
180460,
183390,
185200,
188940,
190750,
194040,
196510,
198060,
202670,
206859,
209980,
213619,
219130,
221760,
222700,
227049,
230340,
234810,
236930,
239030,
241390,
246630,
248200,
252220,
255370,
257160,
258709,
263370,
264280,
266840,
270190,
275640,
277789,
280880,
282680,
283930,
285990,
287870,
290740,
294140,
299760,
305270,
308229,
310160,
311540,
314150,
316159,
316440,
318500,
319750
],
"text": [
null,
"SPEAKER 1: In this sequence, are\ngoing to look at a whole",
"bunch of techniques for\nanalyzing circuits.",
"Think of these as your tool\nchest. So you are embarking on",
"6.002 and going on to build\nlots of useful electronic",
"systems.",
"But before we go and build these\nsystems, much like a",
"carpenter who needs to go build\na house, much like a",
"carpenter has to go and buy a\nset of tools from the local",
"store, we need to go and make\nsure that you have the tools",
"in your tool chest to analyze\nthese circuits.",
"This tool chest will include\nthings like the KVL KCL",
"method, the Node method\nand so on.",
"But before I begin talking about\nthese techniques for",
"your tool chest, I&#39;d like to do\na extremely quick review--",
"as is my usual practice--",
"of what you&#39;ve covered so far.",
"So remember our EECS\nplayground.",
"We&#39;ve gotten into this place by\npromising that we are going",
"to observe the lumped\nmatter discipline.",
"By observing the discipline\nrecall that the complexities",
"of Maxwell&#39;s equations and the\ndifferential equations that",
"you have to solve-- the\npartial differential",
"equations-- goes away.",
"And you&#39;re left with very\nsimple linear equations.",
"And you will see a lot\nof that today.",
"As you make the lumped matter\ndiscipline, you end up with",
"these lumped elements, like\nresistors and voltage",
"sources and so on.",
"And what you do with these\nlumped elements is we can",
"label what are called the\nbranch variables or the",
"terminal variables for these\nlumped elements, OK?",
"So for example, v is the voltage\nacross the element.",
"And i is the current through\nthe element.",
"The power consumed by the\nelement is given by vi.",
"Continuing with our review, the\nlumped matter discipline",
"enables us to create the lumped\ncircuit abstraction.",
"So you take these lumped\nelements and you connect them",
"with ideal wires.",
"So in this case, I have a\nresistor which is a lumped",
"element, a voltage source.",
"And I connect them with\nthese ideal wires.",
"And what you end up with is\ncalled a lumped circuit.",
"But this is your lumped\ncircuit abstraction.",
"Well as we made the transition\nfrom physics to EECS by",
"adhering to the lumped\nmatter discipline.",
"I had discussed in the last\nsequence that Maxwell&#39;s",
"equations turn into very simple\nalgebraic equations.",
"And these are captured by\nKirchoff&#39;s voltage and current",
"laws, called KVL and KCL.",
"So KVL says that for all loops\nin your circuit, the sum of",
"the voltages around the\nloops add up to zero.",
"Similarly for all the nodes in\nthe circuit, the currents that",
"enter into a node\nadd up to zero.",
"And in the same matter, if I\njust summed the currents",
"leaving a node, they also\nadd up to zero.",
"So whether you sum the currents\nentering the node or",
"currents leaving a node, they\nwould add up to zero by KCL.",
"And the beauty of this was by\nadhering to lump matter",
"discipline, recall the\ncomplexities Maxwell&#39;s",
"equations whether an\nintegral form or",
"differential form went away.",
"And we were now left with\nextremely simple algebraic",
"expressions of the sort.",
"And you will see shortly that\nyou will end up solving",
"extremely simple linear\nequations",
"as we analyze circuits.",
"So as one example here\nis a linear circuit.",
"It has one, two, three, four,\nfive, six elements.",
"It&#39;s got a voltage source\nof a voltage v zero.",
"It&#39;s got a resistor, r one\nand so on and so forth.",
"So for this circuit according\nto our abstraction and the",
"laws of KVL and KCL,\nthe following",
"are going to be true.",
"So for instance if I look at\nnode a, then according to KCL,",
"the currents entering the\nnode must be zero.",
"So in other words, the\ncurrent here is ica.",
"And I can sum to that\nthe current",
"entering from the d direction.",
"So that would be plus ida.",
"And then there is a current from\nthe ba direction and iba.",
"Those are going to\nsum to zero.",
"Now I can multiply the whole\nthing by minus 1.",
"And that would give me the sum\nof the currents leaving the",
"node are also going\nto be zero.",
"So that is KCL.",
"Now I can also write KVL in this\ncase for this loop, for",
"instance, here.",
"For this loop I can add up the\nvoltages around the loop.",
"And by KVL they must\nadd up to zero.",
"So for example if I look at\nthe voltage vca, I can add",
"that to the next voltage here.",
"That is to vab and then\nadd that to the",
"final voltage, vbc.",
"And by KCL--",
null,
"so all of those must\nadd up to be zero.",
"Now if you go back to our\ncircuit here that you see on",
"the left hand side, I am going\nto show you a little demo that",
"will look at these currents,\nica, ida, and iba, and also",
"look at the voltages, vcabab\nand bbc and actually go and",
"look at the circuit, make the\nmeasurements, and show that",
"they indeed sum up to zero.",
"Not surprising.",
"KVL and KCL really work.",
"And so the demo should\nalso work.",
"OK.",
"So let&#39;s go and do our demo.",
null
]
}
\ No newline at end of file
common/test/data/full/subs/p2Q6BrNhdh8.srt.sjson 0 → 100644
{
"start": [
0,
6830,
9040,
11810,
15030,
19420,
21690,
24880,
29850,
32409,
35430,
37550,
40240,
44050,
47470,
50910,
52750,
55340,
57870,
59920,
62450,
66320,
70470,
72100,
82700,
84820,
86550,
88890,
93560,
94810,
98620,
100040,
102740,
105880,
108470,
111550,
112830,
116190,
117410,
120620,
122310,
125810,
129720,
132900,
135170,
138020,
141350,
143230,
144480
],
"end": [
6830,
9040,
11809,
15030,
19419,
21690,
24880,
29849,
32409,
35430,
37550,
40239,
44050,
47470,
50910,
52750,
55340,
57870,
59919,
62450,
66320,
70470,
72100,
82699,
84820,
86550,
88890,
93560,
94810,
98620,
100040,
102740,
105880,
108470,
111550,
112830,
116190,
117410,
120619,
122310,
125810,
129720,
132900,
135170,
138019,
141350,
143230,
144480,
152786
],
"text": [
null,
"PROFESSOR ANANT AGARWAL:\nWelcome to MITx, MIT&#39;s",
"worldwide online learning\ninitiative.",
"We are delighted to have you\njoin us for 6.002x: Circuits",
"and Electronics, the inaugural\ncourse of MITx.",
"OK, welcome to 6.002.",
"6.002x is the same as Electronic\nCircuits course",
"taken by MIT students as the\nfirst course in an EE or EECS",
"major at MIT.",
"This course will help you make\nthe transition from physics to",
"electrical engineering.",
"In this course, you will learn\nabout a lot of fun things,",
"including the foundations behind\nmany cool devices, such",
"as the smartphone.",
"The course will be hard and we\nwant you to stick with us.",
"It is our hope that you\nwill have a lot",
"of fun in this course.",
"Let me start by introducing\nyou to our team.",
"I am Anant Agarwal.",
"I am the director of MIT&#39;s\nComputer Science and",
"Artificial Intelligence\nLaboratory or CSAIL.",
"Like most MIT faculty, I have\na wide range of interests,",
"including a fascination\naround chainsaws.",
null,
"GERRY SUSSMAN: Hello, I&#39;m Gerry\nSussman, professor of",
"electrical engineering at MIT.",
"Been a faculty member\nhere since 1973.",
"I build electronics, optics,\ncomputer software, and I",
"repair watches as a hobby.",
null,
"PIOTR MITROS: I&#39;m\nPiotr Mitros.",
"I&#39;m a research scientist at MIT,\nand I was in charge of",
"developing the software\ninfrastructure for MITx.",
"As a graduate student, I spent a\nlot of time traveling around",
"India, Nigeria, and China,\nmostly as part of educational",
"technology projects.",
"So I&#39;m very excited to be\nhelping out with this course.",
"PROFESSOR ANANT AGARWAL: Whether\nwe like chainsaws or",
"watches, we are all passionate\neducators.",
"This course is free.",
"You will have the opportunity\nto earn an MITx pilot",
"certificate with your grade\nat the end of this course.",
"In this experimental first\ncourse of MITx, the",
"certificates are also free.",
"Now, this is a prototype course\nand we welcome your",
"participation and any feedback\nyou might have to improving",
"the learning experience.",
"Let&#39;s get started.",
null
]
}
\ No newline at end of file
common/test/data/full/subs/pFOrD8k9_p4.srt.sjson 0 → 100644
{
"start": [
0,
360,
2460,
6080,
11270,
12700,
16210,
18460,
22750,
26140,
30360,
31480,
35370,
37170,
40710,
43190,
46980,
49050,
52590,
55170,
57100,
59330,
60950,
65450,
69710,
73480,
75100,
77600,
78790,
81330,
82580
],
"end": [
360,
2460,
6080,
11270,
12700,
16210,
18460,
22750,
26140,
30360,
31480,
35370,
37169,
40710,
43190,
46980,
49050,
52589,
55170,
57100,
59330,
60949,
65450,
69710,
73479,
75100,
77600,
78789,
81330,
82580,
83340
],
"text": [
null,
"SPEAKER 1: In this next segment,\nI&#39;d like to show you",
"a little demo of a set of lumped\nelements that you will",
"find in 6002x and in building\nelectronic circuits and",
"systems in general.",
"And these lumped elements have\nbehavior that is completely",
"captured by their V-I\nrelationship.",
"I also want to point out that\nthe behavior of these lumped",
"elements is captured by the\nV-I relationship only for",
"those sorts of questions that\nwe, as electrical engineers,",
"would like to ask.",
"Understand that the V-I relation\ndoesn&#39;t capture all",
"the possible behaviors\nof the element.",
"It only captures those possible\nbehaviors that we, as",
"EEs, generally like to ask.",
"Once I&#39;ve shown you these basic\nV-I relationships, we",
"will do some other fun stuff.",
"I&#39;m going to show you some\nexamples of behavior that the",
"V-I relationship will\nnot capture.",
"We&#39;ll show you what\nwe can predict.",
"For example, we&#39;ll\nshow you how the",
"resistors don&#39;t work sometimes.",
"And sometimes we will show you\nanother example of a cucumber",
"pickle that may behave in ways\nthat you don&#39;t quite expect",
"and whose behavior need not\nnecessarily be captured by",
"your V-I relationship.",
"So I don&#39;t want you to go around\nsaying that you don&#39;t",
"have any fun in this course.",
"So hopefully, you will\nenjoy what you are",
"going to see ahead.",
null
]
}
\ No newline at end of file
common/test/data/full/to_delete 0 → 100644
chapter/Week_10
chapter/Week_11
chapter/Week_12
chapter/Week_4
chapter/Week_5
chapter/Week_6
chapter/Week_7
chapter/Week_8
chapter/Week_9
html/Lab_10B_RC_Filters_Experiment
html/Lab_5B_Mosfet_Amplifier_Experiment
html/Week_10_Tutorials
html/Week_11_Tutorials
html/Week_12_Tutorials
html/Week_4_Tutorials
html/Week_5_Tutorials
html/Week_6_Tutorials
html/Week_7_Tutorials
html/Week_8_Tutorials
html/Week_9_Tutorials
problem/Capacitors_and_Energy_Storage
problem/Curve_Tracer
problem/H10P1_Magnitude_and_Angle
problem/H10P2_Impedances
problem/H10P3_An_L_Network
problem/H11P1_LC_Tank
problem/H11P2_Scope_Probe
problem/H11P3_A_Step_in_Time
problem/H12P1_Current_Source
problem/H12P2_Measuring_Light_
problem/H12P3_Opamps_and_Filter_Design
problem/H4P0_Vacuum_Diode
problem/H4P1_Zener_Regulator
problem/H5P1_Source_Follower_Large_Signal
problem/H5P2_Source_Follower_Small_Signal
problem/H6P1_The_NewFET_device
problem/H6P2_Phase_Inverter
problem/H6P3_Series_and_Parallel_Capacitors
problem/H6P4_Switched_RC
problem/H7P1_Series_and_Parallel_Inductors
problem/H7P2_The_Curse_of_Lead_Inductance
problem/H8P1_Charging_an_Inductor
problem/H8P2_Physiological_Model
problem/H8P3_Memory
problem/H9P1_Response_to_a_Delayed_Impulse
problem/H9P2_An_L_Network
problem/H9P3_Designing_a_Shock_Absorber
problem/Impedance_Frequency_Response
problem/Mosfet_Amplifier
problem/Op_Amps
problem/Propagation_Delay
problem/Resonance
problem/S10E1_Incremental_Voltage
problem/S10E2_two_terminal_connection
problem/S10E3_Small_Signal_Amplifier
problem/S14E1_Response_to_step_down
problem/S14E2_Rise_Time
problem/S14E3_Fall_Time_Constant
problem/S14E4_Fall_Time
problem/S15E1_Review_A_Step_Up
problem/S15E2_Review_A_Step_Down
problem/S15E3_Review_A_Pulse_is_Step_Up_then_Step_Down
problem/S15E4_Area
problem/S15E5_Initial_Conditions
problem/S16E1_Charging_and_Discharging
problem/S16E2_Time_to_Decay
problem/S19E1_Trigonometry_Isn_t_So_Bad
problem/S19E2_Exponentials_are_Nice
problem/S19E3_Complex_Numbers
problem/S19E4_Magnitudes_and_Angles
problem/S20E1_Inductor_Impedance
problem/S20E2_RC_voltage_divider
problem/S20E3_LCR_voltage_divider
problem/S20E4_LCR_voltage_divider_frequency_limits
problem/S21E2_LR_filter
problem/S21E3_Thevenin_Tank
problem/S21E4_AM_Radio_Tuning
problem/S22E1_Which_output_
problem/S22E2_The_filter_is_ringing
problem/S23E2_Inverting_Amplifier_analysis
problem/S23E3_L23AmplifierInputResistance
problem/S24E1_Summing_Amplifier
problem/S24E2_Difference_Amplifier
problem/S24E3_Inverting_Amplifier_Generalized
problem/S24E4_Generalization_to_impedances
problem/S24E5_Generalization_to_nonlinear_elements
problem/S7E1_Linearization
problem/S7E2_Graphs
problem/S7E3_Linearization
problem/S8E0_Dependent_Source
problem/S8E1_Dependent_Current_Source
problem/S8E2_Dependent_Voltage_Source
problem/S9E1_MOSFET_model
problem/S9E2_Amplifier_1
problem/S9E3_MOSFET_Amplifier_2
sequential/Dependent_Sources_and_Amplifiers
sequential/Filters
sequential/Incremental_Analysis
sequential/MOSFET_Amplifiers_Small_signal_model
sequential/MOSFETs_Large_Signals
sequential/Operational_Amplifier_Circuits
sequential/Ramps_Steps_and_Impulses
sequential/Sinusoidal_Steady_State
sequential/Speed_of_Digital_Circuits
sequential/State_and_Memory
sequential/The_Impedance_Model
sequential/The_Operational_Amplifier_Abstraction
sequential/Time_Domain_Versus_Frequency_Domain_Analysis
vertical/vertical_1002
vertical/vertical_1006
vertical/vertical_1010
vertical/vertical_1014
vertical/vertical_1018
vertical/vertical_1022
vertical/vertical_1026
vertical/vertical_1030
vertical/vertical_1034
vertical/vertical_1038
vertical/vertical_1042
vertical/vertical_1046
vertical/vertical_1050
vertical/vertical_1054
vertical/vertical_1058
vertical/vertical_1062
vertical/vertical_1069
vertical/vertical_1073
vertical/vertical_1077
vertical/vertical_1081
vertical/vertical_1085
vertical/vertical_1089
vertical/vertical_1093
vertical/vertical_1097
vertical/vertical_1100
vertical/vertical_1104
vertical/vertical_1108
vertical/vertical_1112
vertical/vertical_1320
vertical/vertical_1324
vertical/vertical_1328
vertical/vertical_1332
vertical/vertical_1336
vertical/vertical_1340
vertical/vertical_1344
vertical/vertical_1348
vertical/vertical_1352
vertical/vertical_1356
vertical/vertical_1360
vertical/vertical_1364
vertical/vertical_1368
vertical/vertical_1373
vertical/vertical_1377
vertical/vertical_1381
vertical/vertical_1385
vertical/vertical_1389
vertical/vertical_1393
vertical/vertical_1403
vertical/vertical_1407
vertical/vertical_1411
vertical/vertical_1415
vertical/vertical_1419
vertical/vertical_1423
vertical/vertical_1427
vertical/vertical_1431
vertical/vertical_1435
vertical/vertical_1439
vertical/vertical_1443
vertical/vertical_1447
vertical/vertical_1451
vertical/vertical_1455
vertical/vertical_1459
vertical/vertical_1463
vertical/vertical_1467
vertical/vertical_1471
vertical/vertical_1479
vertical/vertical_1483
vertical/vertical_1487
vertical/vertical_1491
vertical/vertical_1495
vertical/vertical_1499
vertical/vertical_1503
vertical/vertical_1507
vertical/vertical_1511
vertical/vertical_1515
vertical/vertical_1519
vertical/vertical_1523
vertical/vertical_1527
vertical/vertical_1531
vertical/vertical_1535
vertical/vertical_1539
vertical/vertical_1543
vertical/vertical_1547
vertical/vertical_1551
vertical/vertical_1555
vertical/vertical_1559
vertical/vertical_1563
vertical/vertical_1566
vertical/vertical_1570
vertical/vertical_1574
vertical/vertical_1578
vertical/vertical_1582
vertical/vertical_1586
vertical/vertical_1590
vertical/vertical_1594
vertical/vertical_1598
vertical/vertical_1603
vertical/vertical_1607
vertical/vertical_1611
vertical/vertical_1615
vertical/vertical_1619
vertical/vertical_1623
vertical/vertical_1627
vertical/vertical_1631
vertical/vertical_1635
vertical/vertical_1639
vertical/vertical_1643
vertical/vertical_1647
vertical/vertical_1651
vertical/vertical_1655
vertical/vertical_1659
vertical/vertical_1663
vertical/vertical_1667
vertical/vertical_1671
vertical/vertical_1675
vertical/vertical_1679
vertical/vertical_1683
vertical/vertical_1687
vertical/vertical_1691
vertical/vertical_1695
vertical/vertical_1699
vertical/vertical_1703
vertical/vertical_1707
vertical/vertical_1711
vertical/vertical_1715
vertical/vertical_1719
vertical/vertical_1723
vertical/vertical_1727
vertical/vertical_1731
vertical/vertical_1735
vertical/vertical_1739
vertical/vertical_1743
vertical/vertical_1747
vertical/vertical_1751
vertical/vertical_1755
vertical/vertical_1759
vertical/vertical_1763
vertical/vertical_1767
vertical/vertical_431
vertical/vertical_435
vertical/vertical_439
vertical/vertical_443
vertical/vertical_447
vertical/vertical_451
vertical/vertical_455
vertical/vertical_459
vertical/vertical_463
vertical/vertical_469
vertical/vertical_475
vertical/vertical_479
vertical/vertical_483
vertical/vertical_487
vertical/vertical_491
vertical/vertical_495
vertical/vertical_504
vertical/vertical_508
vertical/vertical_512
vertical/vertical_516
vertical/vertical_520
vertical/vertical_524
vertical/vertical_530
vertical/vertical_534
vertical/vertical_538
vertical/vertical_542
vertical/vertical_546
vertical/vertical_550
vertical/vertical_554
vertical/vertical_558
vertical/vertical_562
vertical/vertical_566
vertical/vertical_570
vertical/vertical_577
vertical/vertical_581
vertical/vertical_585
vertical/vertical_589
vertical/vertical_593
vertical/vertical_597
vertical/vertical_601
vertical/vertical_605
vertical/vertical_609
vertical/vertical_613
vertical/vertical_617
vertical/vertical_621
vertical/vertical_625
vertical/vertical_629
vertical/vertical_633
vertical/vertical_637
vertical/vertical_641
vertical/vertical_645
vertical/vertical_649
vertical/vertical_653
vertical/vertical_660
vertical/vertical_664
vertical/vertical_668
vertical/vertical_672
vertical/vertical_676
vertical/vertical_680
vertical/vertical_684
vertical/vertical_688
vertical/vertical_692
vertical/vertical_696
vertical/vertical_700
vertical/vertical_704
vertical/vertical_886
vertical/vertical_890
vertical/vertical_894
vertical/vertical_898
vertical/vertical_902
vertical/vertical_906
vertical/vertical_910
vertical/vertical_914
vertical/vertical_918
vertical/vertical_922
vertical/vertical_926
vertical/vertical_930
vertical/vertical_938
vertical/vertical_942
vertical/vertical_946
vertical/vertical_950
vertical/vertical_954
vertical/vertical_958
vertical/vertical_962
vertical/vertical_966
vertical/vertical_970
vertical/vertical_974
vertical/vertical_978
vertical/vertical_982
vertical/vertical_986
vertical/vertical_990
vertical/vertical_994
vertical/vertical_998
common/test/data/full/vertical/vertical_58.xml 0 → 100644
<sequential>
<video youtube="1.50:8kARlsUt9lM,1.25:4cLA-IME32w,1.0:pFOrD8k9_p4,0.75:CcgAYu0n0bg" slug="S1V9_Demo_Setup_-_Lumped_Elements" name="S1V9: Demo Setup - Lumped Elements"/>
<customtag tag="S1" slug="discuss_59">
<impl>discuss</impl>
</customtag>
<customtag page="29" slug="book_60">
<impl>book</impl>
</customtag>
<customtag lecnum="1" slug="slides_61">
<impl>slides</impl>
</customtag>
</sequential>
common/test/data/full/vertical/vertical_89.xml 0 → 100644
<sequential>
<html slug="html_90">
<h1> </h1>
</html>
<video youtube="1.50:vl9xrfxcr38,1.25:qxNX4REGqx4,1.0:BGU1poJDgOY,0.75:8rK9vnpystQ" slug="S1V14_Summary" name="S1V14: Summary"/>
<customtag tag="S1" slug="discuss_91">
<impl>discuss</impl>
</customtag>
<customtag page="70" slug="book_92">
<impl>book</impl>
</customtag>
<customtag lecnum="1" slug="slides_93">
<impl>slides</impl>
</customtag>
</sequential>
common/test/data/full/vertical/vertical_94.xml 0 → 100644
<sequential>
<video youtube="0.75:3NIegrCmA5k,1.0:eLAyO33baQ8,1.25:m1zWi_sh4Aw,1.50:EG-fRTJln_E" slug="S2V1_Review_KVL_KCL" name="S2V1: Review KVL, KCL"/>
<customtag tag="S2" slug="discuss_95">
<impl>discuss</impl>
</customtag>
<customtag page="54" slug="book_96">
<impl>book</impl>
</customtag>
<customtag lecnum="2" slug="slides_97">
<impl>slides</impl>
</customtag>
</sequential>
common/test/data/full/vertical/vertical_98.xml 0 → 100644
<sequential>
<video youtube="0.75:S_1NaY5te8Q,1.0:G_2F9wivspM,1.25:b-r7dISY-Uc,1.50:jjxHom0oXWk" slug="S2V2_Demo-_KVL_KCL" name="S2V2: Demo- KVL, KCL"/>
<customtag tag="S2" slug="discuss_99">
<impl>discuss</impl>
</customtag>
<customtag page="56" slug="book_100">
<impl>book</impl>
</customtag>
<customtag lecnum="2" slug="slides_101">
<impl>slides</impl>
</customtag>
</sequential>
Markdown is supported
0% or
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or to comment